The Student Room Group

Integral of the Logarithm of Dirac Delta function?

ln(δ(x))dx \int ln(\delta (x)) dx

over infinity. I understand the properties of a Dirac delta, it is zero everywhere except when its argument is equal to zero, where it is infinity. The integral of a dirac delta function over all values of it argument is equal to one. But what about when it's logged? I'm having a hard time grasping that, from my notes it SHOULD be equal to zero. I'm guessing because we're left with

ln(δ(x))dx=ln(1)=0 \int ln(\delta (x)) dx = ln(1) = 0

But how can I know for definite the integral is ln(1)?

Reply 1

No replies in 11 years is crazy, good luck tho.

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