If I've started with the following volumes:
Ethanoic Acid - 30cm3
Ethanol - 30cm3
Ethyl Ethanoate - 0cm3
HCl (concentration: 1.0 mol dm3) - 10cm3
Water - 30cm3
We were asked to work out the moles of each substance before the equilibrium was achieved; the values achieved were out of 100cm3 (total volume of reaction mixture) so they had to be by 10 to have them out of 1dm3.
Then they were reacted together to reach equilibrium. Afterwards, 1cm3 of the solution was taken out and put into a conical flask with 25cm3 of deionized/distilled water.
It took 7cm3 of Sodium Hydroxide to turn the solution alkaline. Does that mean there is 7x10-4mol within that 1cm3 and would that have to be multiplied by a thousand to get it in terms of dm3 like before with the 100cm3? So, from this, how would I calculate the concentrations of each substance at equilibrium? And hence calculate the value of Kc? (I'm basically clueless with this since we were just given this to work out without any explanation, so any form of help would be greatly appreciated!!)
*another thing, originally we had to work out the moles using the volumes and densities:
Ethanoic Acid: 1.05gcm3
Ethyl Ethanoate: 0.92gcm3
And then had to work out concentrations (don't know why that was needed) but with the HCl, even though it states the concentration being 1moldm3, we somehow ended up with 0.1moldm3, it's just one giant mess*