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    OK, got that answer.

    Now I'm stuck on this equation:

    ln(3x + 6) = 4y

    Now I need to find x in the terms of others. Any help?
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    (Original post by 2776)
    OK, got that answer.

    Now I'm stuck on this equation:

    ln(3x + 6) = 4y

    Now I need to find x in the terms of others. Any help?
    ln(3x + 6) = 4y
    3x + 6 = e^4y
    3x = e^4y - 6

    x = (e^4y - 6)/3
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    (Original post by bono)
    ln(3x + 6) = 4y
    3x + 6 = e^4y
    3x = e^4y - 6

    x = (e^4y - 6)/3
    Of course! My brain has now officially stopped working.
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    (Original post by bono)
    ln(3x + 6) = 4y
    3x + 6 = e^4y
    3x = e^4y - 6

    x = (e^4y - 6)/3
    I shouldn't be insulting Phil, I am sure there is another way to go further.....

    EDIT: Hehehe...
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    (Original post by 2776)
    Of course! My brain has now officially stopped working.
    Don't worry Phil, I've had these moments
 
 
 

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