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Can we reach 2013 posts before 2013 tonight? watch

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    600

    edit: lol nope
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    Anyone want to guess who'll get 1000th?
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    (Original post by Rahul.S)
    stop quoting me KUTI

    fireworks aint on until 12
    Oh my God, it's you! :eek:
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    Damn :rofl: we all missed it...
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    (Original post by areebmazhar)
    any single girls want to go out with me?

    Ermm...I'll do your homework for you...and give you a foot massage...and..

    I'll even pay you goddamn it :adore:
    what? :eek:
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    haha watch how this thread gets stuck at 998 because everyone will want post #1000
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    (Original post by TheSownRose)
    Anyone want to guess who'll get 1000th?
    Evil Fish is my guess
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    I will get the 700th post!
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    (Original post by TheSownRose)
    Added to the list.
    Can you add me to the list? 21.28.31 on the 31/12/12.
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    (Original post by Rahul.S)
    stop quoting me KUTI

    fireworks aint on until 12
    GO away KUTA!!!!!!!!!!!!!!!!!!!!!
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    (Original post by Little Tail Chaser)
    Evil Fish is my guess
    :rofl: I won't
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    Don't really know what to post...

    Potato.
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    Would be easy to do so...
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    What's been everyone's favourite humourous news story of the year?
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    (Original post by TheSownRose)
    Anyone want to guess who'll get 1000th?
    Me (duh)
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    (Original post by \/ibhav)
    Can you add me to the list? 21.28.31 on the 31/12/12.
    Sorry - I did add you, but forgot to tell you.

    You are on the list.
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    (Original post by Little Tail Chaser)
    Evil Fish is my guess
    I'd say your best bet would be me, I WILL get this! :sparta:
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    (Original post by areebmazhar)
    any single girls want to go out with me?

    Ermm...I'll do your homework for you...and give you a foot massage...and..

    I'll even pay you goddamn it :adore:
    Why not?

    But you're in Sheffield and I'm in London...
    :cry:
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    (Original post by Zango11)
    I think we'll reach the 1000th post at 22:04
    modelling the relationship of comments as a function of time and considering the non-relativistic self-interactions in the Hamiltonian field delineate the relationship between the field operators

     T = - \frac{\hbar^2}{2m} \int d^3\!r \ \phi^\dagger(\mathbf{r}) \nabla^2 \phi(\mathbf{r}) + \frac{1}{2}\int\!d^3\!r \int\!d^3\!r' \; \phi^\dagger(\mathbf{r}) \phi^\dagger(\mathbf{r}') U(|\mathbf{r} - \mathbf{r}'|) \phi(\mathbf{r'}) \phi(\mathbf{r})

    I concur
 
 
 
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