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    For the E-Z isomerism you take the biggest group on opposite ends of the double bond. So on the left hand side in the drawing, it'd be the methyl and on the right side it'd be the ethyl. So it's the E-isomer.
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    Z stereo isomerism

    Edited: person above said E but I don't know why?
    The same alkyl group is on two different carbon atoms and on the same side so why not
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    (Original post by loknath)
    Z stereo isomerism

    Edited: person above said E but I don't know why?
    The same alkyl group is on two different carbon atoms and on the same side so why not
    As I've said, with the drawing as it is above, the bigger group by molecular weight on the left of the double bond is the methyl, and on the right it's the ethyl group.
    E-Z isomerism is determined by the molecular weights of the substituent groups on each end of the double bond, so in this case we consider the methyl on the left and the ethyl on the right. Mexican accent, Es opposite, they're opposite hence it's the E-isomer.


    Yes, I do remember E-Z via a mexican accent and a german accent (on ze zame zide).

    edit: I've put it through Chemsketch to generate the name, and that confirms that it's the E-isomer.
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    (Original post by Stiff Little Fingers)
    For the E-Z isomerism you take the biggest group on opposite ends of the double bond. So on the left hand side in the drawing, it'd be the methyl and on the right side it'd be the ethyl. So it's the E-isomer.

    (Original post by loknath)
    Z stereo isomerism

    Edited: person above said E but I don't know why?
    The same alkyl group is on two different carbon atoms and on the same side so why not
    Hey thanks completely forgot the stuff about molecular weight. Thanks again
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    (Original post by Stiff Little Fingers)
    As I've said, with the drawing as it is above, the bigger group by molecular weight on the left of the double bond is the methyl, and on the right it's the ethyl group.
    E-Z isomerism is determined by the molecular weights of the substituent groups on each end of the double bond, so in this case we consider the methyl on the left and the ethyl on the right. Mexican accent, Es opposite, they're opposite hence it's the E-isomer.


    Yes, I do remember E-Z via a mexican accent and a german accent (on ze zame zide).

    edit: I've put it through Chemsketch to generate the name, and that confirms that it's the E-isomer.

    Thanks - that clears my confusion
    And sorry
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    (Original post by CasualSoul)
    Please see attatched
    Definitely E
 
 
 
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