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Help with Question!!! C3 MATHS OCR 2008 PAPER QUESTION 6(iii) Watch

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    Hi can anyone please help me with question 6(iii), I'm not quite sure how to get the solutions. Can someone please explain step-by-step. I have attached a picture of the question. Thanks
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    (Original post by sirifromapple)
    Hi can anyone please help me with question 6(iii), I'm not quite sure how to get the solutions. Can someone please explain step-by-step. I have attached a picture of the question. Thanks
    Can you explain what you tried?
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    (Original post by sirifromapple)
    Hi can anyone please help me with question 6(iii), I'm not quite sure how to get the solutions. Can someone please explain step-by-step. I have attached a picture of the question. Thanks
    Assuming you've answered part ii) correctly, do you understand what the modulus sign does?
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    y=-f(x) is a reflection of y=f(x) in the x axis

    y=f(x-k) is a translation of y=f(x) by k units in the positive x direction

    You need to think carefully about how the transformations are applied as you are going from y=-\sin^{-1}(x-1) to y=\sin^{-1}(x) not the other way round.
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    Thanks for the responses. I know that I have to reflect the negative part of the graph in the x-axis for part (ii), and i'm good with part 1. But how do I go about finding the solutions for part (iii).
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    (Original post by sirifromapple)
    Thanks for the responses. I know that I have to reflect the negative part of the graph in the x-axis for part (ii), and i'm good with part 1. But how do I go about finding the solutions for part (iii).
    Either \sin^{-1}(x-1)=-\frac{\pi}{3} or \sin^{-1}(x-1)=\frac{\pi}{3}

    Solve these two trigonometric equations.

    Make sure your calculator is in radians mode.

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    You can take the sine of both sides of the equations
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    thanks guys, gottit
 
 
 
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