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    An important reaction which occurs in the catalytic converter of a car is


    2CO(g) + 2NO(g) ---> 2CO2(g) + N2(g)


    In this reaction, when 500 cm3
    of CO reacts with 500 cm3
    of NO at 650 °C (the operating temperature of the catalyst) and at 1 atm, the total volume of gases produced

    at the same temperature and pressure is

    A 500 cm3
    B 750 cm3
    C 1000 cm3
    D impossible to calculate without knowing the molar volume of gases under these
    conditions.


    The answer is B
    how would you calculate this please help me

    Thank You..
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    You've got 4 mols of gas on the left side of the equation and 3 mols on the right side. 4 mols of gas at this temperature and pressure is 1000cm2 (500 of CO + 500 of NO), so 1 mol would be 250cm2. On the right, you've got 3 mols of gas, so 3 x 250 = 750cm2. Hope that makes sense.
 
 
 
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