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    (Original post by ZoeLouise15)
    I got that one too! What did people do for 6b? Was it integration as I didn't know what to do.
    I got something like

    2x^5 + 2x^3 + something I can't remember -1

    You had to integrate to find the original equation of the curve and then subsititue the coordinates of P to find out the value of C
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    Well, I've done 6b wrong then and probably 6a. Question 6 and question 7 i found really hard. What did you get for 7a?
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    (Original post by Ferrari_1996)
    You're probably right. I didn't know how to work out the vertex. I should've revised more. How did you work out the vertex?
    The completed square of the equation was (x-3)^2 + 2

    Therefore to make the bracket = 0, you have to put a positive 3 in so 3 is the x value and the 2 outside the bracket is the y value of the vertex.
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    The question asked for the geometric transformation of y = (x-3)^2 + 2 onto y = x^2

    (Original post by the_googly)
    I'm sure the answer is 3 to the right and 2 up. After you have completed the square, the vertex is (3,2). The vertx of the y=x^2 is (0,0) therefore the graph has been translated by the vector [3,2]
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    (Original post by the_googly)
    Should it be positive 3 and positive 2?
    No, because the question asked for the geometric transformation that mapped y = x^2 - 6x + 11 onto the graph of y = x^2 not y=x^2 onto the graph of y = x^2 - 6x + 11.

    y=x^2 onto the graph of y = x^2 - 6x + 11
    Translation (3,2)

    y = x^2 - 6x + 11 onto the graph of y = x^2
    Translation (-3,-2)
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    (Original post by ThomSDK)
    From what ive heard it was an easy paper in general and i dont believe i dropped any marks. They cannot however make the A boundary above 67/75 due to the gap they must leave for students getting above 90% aiming for A* in maths and the grade boundaries are normally 6 or 7 marks away from eachother so im assuming

    62-64 for an A
    55-57 for a B
    47-49 for a C
    Etc
    I really hope that I got a B. Highly doubt I'm going to get an A considering I don't remember doing the integration question meaning I lost 5 marks there. And I didn't do the translation question correctly either. I didn't even know how to show that k = -4 in the first question! And I obviously dropped marks in other parts of the test paper
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    (Original post by JimboTech)
    The question asked for the geometric transformation of y = (x-3)^2 + 2 onto y = x^2

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    I think I read the question wrong now
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    Oh well at least I'll get one mark for saying 'translation' :-)

    Lost two marks very stupidly there

    Definately messed up on the second surd question aswell, anybody remember it?
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    +5x :')

    (Original post by the_googly)
    I got something like<br />
    <br />
    2x^5 + 2x^3 + something I can't remember -1<br />
    <br />
    You had to integrate to find the original equation of the curve and then subsititue the coordinates of P to find out the value of C
    Yeah, I know a few people who did, I only noticed myself when checking my answers which I rarely do

    (Original post by the_googly)
    I think I read the question wrong now<img src="images/smilies/angry.gif" border="0" alt="" title="" smilieid="12" class="inlineimg" />
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    (Original post by the_googly)
    Should it be positive 3 and positive 2?
    no, as it was asking for the translation from the graph to y=x2, so it was -3, -2, dw, i think a lot of people got that one wrong, its confusing as they normally ask for it the other way round
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    (Original post by the_googly)
    The completed square of the equation was (x-3)^2 + 2

    Therefore to make the bracket = 0, you have to put a positive 3 in so 3 is the x value and the 2 outside the bracket is the y value of the vertex.
    Wasn't it (x-3)^2 - 9 + 11 or something like that?
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    (Original post by Fillly)
    Ah nvm, thats a mark ive lost. However i found this paper fairly decent, anyone else get the c on the integration question to be -1?
    yes i got that!!
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    How many marks was the translation one?
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    (Original post by daniya12)
    no, as it was asking for the translation from the graph to y=x2, so it was -3, -2, dw, i think a lot of people got that one wrong, its confusing as they normally ask for it the other way round
    Yeah that question was like as though I had already seen it in a past paper lol, lesson learnt :-)
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    (Original post by Fillly)
    How many marks was the translation one?
    3- a mark for mentioning translation, and then 1 mark for each correct vector value
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    (Original post by Ferrari_1996)
    Wasn't it (x-3)^2 - 9 + 11 or something like that?
    -9+11 = 2
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    (Original post by Fillly)
    How many marks was the translation one?
    It was 3
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    Ah well, Ive got a mark on that one for sure so not a total disaster then
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    (Original post by the_googly)
    -9+11 = 2
    Oh yeah I think I did simplify the -9 + 11 to +2. You did get -9 +11 before you changed it to +2, right?
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    I hope everybody remembered to put a statement after the questions where you have to find the remainder of the polynomial and prove a factor of a polynomial.
 
 
 
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