coulomb's law
A charge of -1.602x10^-19 and a charge of +1.602x10^-19 (+ve charge on the right) separated by 1nm. What is the electric field strength at 5nm to the right of the positive charge.
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If there were no -ve charge I know how to calculate the field strength to the right of the +ve charge (Q1/4πεr^2) but I'm not sure how the presence of the negative charge will affect this value.
Thanks
-----
If there were no -ve charge I know how to calculate the field strength to the right of the +ve charge (Q1/4πεr^2) but I'm not sure how the presence of the negative charge will affect this value.
Thanks
Managed it in the end.
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