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    The only thing im worried is acids,bases and salts.
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    official thread http://www.thestudentroom.co.uk/show...2233530&page=4
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    (Original post by LemonFish)
    Go on the My-GCSEScience website or search for it on youtube, there will be some videos there which can help you with electrolysis
    thanks i used it now im an expert
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    The test was okay today actually, the six mark question was a nice one as all the information was there. Oh and nobody in my school managed to work out the empiracal formula, I got N (1) Cu(3)? Anyone else get that? The first question was quite tricky too...?
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    (Original post by ethanethan)
    The test was okay today actually, the six mark question was a nice one as all the information was there. Oh and nobody in my school managed to work out the empiracal formula, I got N (1) Cu(3)? Anyone else get that? The first question was quite tricky too...?
    I also got N (1) C (3) :yep:

    And yeah, the six mark question was awesome. I was so glad it was something like that, most of the info was there, just had to add a tad of your own knowledge!

    The first question, I think, the cloudiness was due the solid compound (I can't remember the name of it) because it's a precipitate. I wrote something along those lines. What did you write?
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    (Original post by ethanethan)
    The test was okay today actually, the six mark question was a nice one as all the information was there. Oh and nobody in my school managed to work out the empiracal formula, I got N (1) Cu(3)? Anyone else get that? The first question was quite tricky too...?
    I got cu3n too I thought the first one was tricky too, I said a precipitate is produced but I'm not sure it's right


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    What did you guys get for the second last question? The calculation one...


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    If memory serves correctly:

    2Fe + ??? --> 2FeCl3 + ???
    how many grams of copper chloride does 11.2 grams of copper make.

    • the mole of Fe (nFe) = mass / ar = 11.2 / (56) = 0.2
    • the mole of FeCl3 (nFeCl3) = nFe = 0.2
    • therefore, mass = nFeCl3 * Ar = 0.2*(56+(35.5*3)) = 32.5
    Answer... mass = 32.5 grams
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    (Original post by Tayla)
    I got cu3n too I thought the first one was tricky too, I said a precipitate is produced but I'm not sure it's right


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    On the first question, the products of the reaction were: --> H2O(aq) + NaCl(aq) + S(s)
    as Sulfur was the only element to be in solid form (as opposed to aqueous), I too assumed it was a precipitate (insoluble salt), which are generally brightly coloured.

    I also got Cu3N as the empirical formula, lets hope it's right
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    I got Cu3N for that one too! ^.^

    Did anyone else struggle with the questions about Copper Sulfate and the crystals? If anyone could enlighten me about that section, that would be great!

    Otherwise, I thought the paper was fairly easy. Hoping for low grade boundaries and high marks!
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    Is there any particular part of the Copper Sulphate crystals question you want to be 'enlightened' on, or just a general overview of the process.

    As far as I can remember, sulphuric acid and copper hydroxide(in excess) were mixed together, they were heated (this was either to speed it up/provide activation energy or because it's endothermic - I don't know). Next the solution was FILTERED to remove the excess copper hydroxide, after this, the solution was EVAPORATED to remove half of the water & was left to CRYSTALLISE.

    the formulae for a neutralisation reaction is: (H+) + (OH-) --> h20
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    (Original post by IsaacIIV)
    If memory serves correctly:

    2Fe + ??? --> 2FeCl3 + ???
    how many grams of copper chloride does 11.2 grams of copper make.

    • the mole of Fe (nFe) = mass / ar = 11.2 / (56) = 0.2
    • the mole of FeCl3 (nFeCl3) = nFe = 0.2
    • therefore, mass = nFeCl3 * Ar = 0.2*(56+(35.5*3)) = 32.5
    Answer... mass = 32.5 grams
    Thanks for that answer. Such a relief...I got 32.5 too.


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    (Original post by IsaacIIV)
    Is there any particular part of the Copper Sulphate crystals question you want to be 'enlightened' on, or just a general overview of the process.

    As far as I can remember, sulphuric acid and copper hydroxide(in excess) were mixed together, they were heated (this was either to speed it up/provide activation energy or because it's endothermic - I don't know). Next the solution was FILTERED to remove the excess copper hydroxide, after this, the solution was EVAPORATED to remove half of the water & was left to CRYSTALLISE.

    the formulae for a neutralisation reaction is: (H+) + (OH-) --> h20
    I put the reversible reaction arrows in the neutralisation equation. Hope it doesn't loose me marks....but thanks yet again! You're absolutely correct with the crystals process....should get maximum marks on that


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    (Original post by ethanethan)
    The test was okay today actually, the six mark question was a nice one as all the information was there. Oh and nobody in my school managed to work out the empiracal formula, I got N (1) Cu(3)? Anyone else get that? The first question was quite tricky too...?
    Yeah i got that too
 
 
 
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