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Few Higher Qs: algebra, denominator rationalising, simultaneous equation, factorising Watch

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    (Original post by ozzyoscy)
    Yikes, no need to be a **** about it. If removing like terms isn't one of the processes to finding the answer, then I don't know the answer.
    You have an equation with only x in it, so solve it to find x.
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    (Original post by james22)
    You have an equation with only x in it, so solve it to find x.
    Yup.
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    (Original post by ozzyoscy)
    Yup.
    What do you get?
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    (Original post by james22)
    What do you get?
    I've got it down to y^2 = 5x^2 + 5x + 6. I'm not sure what else more I can simplify or convert.
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    (Original post by ozzyoscy)
    I've got it down to y^2 = 5x^2 + 5x + 6. I'm not sure what else more I can simplify or convert.
    No, that is an equation in x and y, you need one in olny x. Look at tenofthem's previous post:

    (Original post by TenOfThem)
    This is correct so you have 9x^2+6x+1=4x^2-x+7

    Which you need to solve to find x



    This is nonsense
    The equation there is only in terms of x so can be solved to find x. When solving simultanious equations you have to get to an equation with only 1 unknown.
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    (Original post by james22)
    No, that is an equation in x and y, you need one in olny x. Look at tenofthem's previous post:

    The equation there is only in terms of x so can be solved to find x. When solving simultanious equations you have to get to an equation with only 1 unknown.
    So how do I solve it? I'm doing something wrong.

    If I remove like terms there, I get 5x^2 + 8x - 6 = x
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    (Original post by ozzyoscy)
    So how do I solve it? I'm doing something wrong.
    Just move all the terms to one side so you have something=0 then simplify and you will have a quadratic equation in x. Can you solve it now?
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    (Original post by ozzyoscy)
    If I remove like terms there, I get 5x^2 + 8x - 6 = x
    OK so now move that x across so you get 5x^2+7x-6=0 and solve it how you would solve any other quadratic equation.
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    (Original post by james22)
    OK so now move that x across so you get 5x^2+7x-6=0 and solve it how you would solve any other quadratic equation.
    I get (5x - 3)(x + 2)
 
 
 
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