Hey there! Sign in to join this conversationNew here? Join for free
    • Thread Starter
    Offline

    15
    ReputationRep:
    please see attatched. I pretty much understand how to use quotient rule however simple brackets is letting me down

    its looks smallyou neeed to click on it and then click on it again so it appears in another window then click on it then a magnifying glass appears and if you click onti it allows you to zoom in as many times as you want
    Attached Images
     
    Offline

    16
    ReputationRep:
    (Original post by CasualSoul)
    please see attatched. I pretty much understand how to use quotient rule however simple brackets is letting me down

    its looks smallyou neeed to click on it and then click on it again so it appears in another window then click on it then a magnifying glass appears and if you click onti it allows you to zoom in as many times as you want
    That is the numerator, yes
    • Thread Starter
    Offline

    15
    ReputationRep:
    (Original post by TenOfThem)
    That is the numerator, yes
    which one, the one where it's all to the minus?]

    or the one where its just the (2x...etc bit to the minus. Also wow fast reply!!!
    Offline

    16
    ReputationRep:
    (Original post by CasualSoul)
    which one, the one where it's all to the minus?
    I am not sure what you mean

    they are all the same

    -(2x-x^2)^{-\frac{1}{2}}(1-x)

    Though I would be inclined to take the -ve in and give the numerator as

    (2x-x^2)^{-\frac{1}{2}}(x-1)
    • Thread Starter
    Offline

    15
    ReputationRep:
    (Original post by TenOfThem)
    I am not sure what you mean

    they are all the same

    -(2x-x^2)^{-\frac{1}{2}}(1-x)

    Though I would be inclined to take the -ve in and give the numerator as

    (2x-x^2)^{-\frac{1}{2}}(x-1)

    oh yeah rightlol

    Thanks ! (1+ rating)
    • Thread Starter
    Offline

    15
    ReputationRep:
    (Original post by TenOfThem)
    I am not sure what you mean

    they are all the same

    -(2x-x^2)^{-\frac{1}{2}}(1-x)

    Though I would be inclined to take the -ve in and give the numerator as

    (2x-x^2)^{-\frac{1}{2}}(x-1)
    Hey, I was just wondering is there any particular reason why you'd be inclined to do this or is it just out of habit?
    Offline

    16
    ReputationRep:
    (Original post by CasualSoul)
    Hey, I was just wondering is there any particular reason why you'd be inclined to do this or is it just out of habit?
    tidier
    • Thread Starter
    Offline

    15
    ReputationRep:
    (Original post by TenOfThem)
    tidier
    okay. Ta
 
 
 
  • See more of what you like on The Student Room

    You can personalise what you see on TSR. Tell us a little about yourself to get started.

  • Poll
    Will you be richer or poorer than your parents?
    Useful resources

    Make your revision easier

    Maths

    Maths Forum posting guidelines

    Not sure where to post? Read the updated guidelines here

    Equations

    How to use LaTex

    Writing equations the easy way

    Student revising

    Study habits of A* students

    Top tips from students who have already aced their exams

    Study Planner

    Create your own Study Planner

    Never miss a deadline again

    Polling station sign

    Thinking about a maths degree?

    Chat with other maths applicants

    Can you help? Study help unanswered threads

    Groups associated with this forum:

    View associated groups
  • See more of what you like on The Student Room

    You can personalise what you see on TSR. Tell us a little about yourself to get started.

  • The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

    Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

    Quick reply
    Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.