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    How do you apply the potential divider formula? I never know what resistor to assign as R1 or R2. It's just fluke if I get the answer correct..

    the equation is: vout=vin x R1(R1+R2)

    Thanks people
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    Your equation is incorrect. It should be: V_{out}=\frac{V_{in} \times R_{1}}{R_{1}+R_{2}}

    R1 is the resistor which comes after the divider. R2 is the resistor which comes before the divider.

    See this diagram:
    http://upload.wikimedia.org/wikipedi...ge_divider.png

    Replace Z1 with R2 and Z2 with R1

    Hope this helps
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    (Original post by crc290)
    Your equation is incorrect. It should be: V_{out}=\frac{V_{in} \times R_{1}}{R_{1}+R_{2}}

    R1 is the resistor which comes after the divider. R2 is the resistor which comes before the divider.

    See this diagram:
    http://upload.wikimedia.org/wikipedi...ge_divider.png

    Replace Z1 with R2 and Z2 with R1

    Hope this helps
    you are a life saver! thank you!
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    (Original post by polaritymolecule)
    you are a life saver! thank you!
    You're welcome
 
 
 
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