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    Name:  phy help n.png
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    I thought the voltage splits, so i found out the internal resistance r then found the voltage for 6ohms which is 3v and therefore the parallel would be 6v.

    Turns out the parallel is 1 volt, which i dont understand.
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    (Original post by Tynos)
    Name:  phy help n.png
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    I thought the voltage splits, so i found out the internal resistance r then found the voltage for 6ohms which is 3v and therefore the parallel would be 6v.

    Turns out the parallel is 1 volt, which i dont understand.
    Just had a quick look at it, you minus the voltage the 6ohm resistor from the source voltage, then the voltage remaining is the same across both resistors in parallel isn't it
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    wait it's easier than that. total R in parallel is 1/2+1/2, then V=IR which is 1x1=1
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    (Original post by jonnyb123)
    wait it's easier than that. total R in parallel is 1/2+1/2, then V=IR which is 1x1=1

    Oh yeah ty.
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    If the current through the parallel combination of resistors in 1.0A (as the circuit is in series), because the resistors have same resistance, the current splits equally into 2 so the current through one resistor in the parallel combination is 0.5A

    using V=IR, V= 0.5A x 2 ohms = 1V

    As the resistors are in parallel, the pd across both is the same.

    or similarly, the 1/R1 + 1/R2 = 1/R equation can be used, giving you a eqvialent resistance of 1 ohm
    1 ohm x 1 A equals 1 V

    I hope that's the answer :P
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    (Original post by Tynos)
    Oh yeah ty.
    You're welcome
 
 
 
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