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# Another circuit watch

1. I thought the voltage splits, so i found out the internal resistance r then found the voltage for 6ohms which is 3v and therefore the parallel would be 6v.

Turns out the parallel is 1 volt, which i dont understand.
2. (Original post by Tynos)

I thought the voltage splits, so i found out the internal resistance r then found the voltage for 6ohms which is 3v and therefore the parallel would be 6v.

Turns out the parallel is 1 volt, which i dont understand.
Just had a quick look at it, you minus the voltage the 6ohm resistor from the source voltage, then the voltage remaining is the same across both resistors in parallel isn't it
3. wait it's easier than that. total R in parallel is 1/2+1/2, then V=IR which is 1x1=1
4. (Original post by jonnyb123)
wait it's easier than that. total R in parallel is 1/2+1/2, then V=IR which is 1x1=1

Oh yeah ty.
5. If the current through the parallel combination of resistors in 1.0A (as the circuit is in series), because the resistors have same resistance, the current splits equally into 2 so the current through one resistor in the parallel combination is 0.5A

using V=IR, V= 0.5A x 2 ohms = 1V

As the resistors are in parallel, the pd across both is the same.

or similarly, the 1/R1 + 1/R2 = 1/R equation can be used, giving you a eqvialent resistance of 1 ohm
1 ohm x 1 A equals 1 V

I hope that's the answer :P
6. (Original post by Tynos)
Oh yeah ty.
You're welcome

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