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    I've got to a point in a question where I have to divide root 68 by 2.
    Do I need to make 2, root 2 or just leave it?

    Thanks.
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     \frac{\sqrt{68}}{2} = \frac{\sqrt{68}}{\sqrt{2^2}} =\sqrt{\frac{68}{2^2}}

    I hope that helps.
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    2=\sqrt 4

    \frac{\sqrt{68}}{\sqrt{4}}=\sqrt  {\frac{68}{4}}=?
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    well first simplify root 68 by splitting it up so you would simplify it down to 2 x root 17.
    2 x root 17 over 2 would be =root 17.

    So simplify the surd to start with and then they should cancel out, especially if its C1 im guessing.
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    Thanks thats what I thought but I wasn't certain.
 
 
 
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Updated: January 6, 2013
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