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M1 - particles on an inclined plane

Right so im lost on this question because of the direction of the force, usually these are fairly straight forward but this has thrown me.

What do you do when you have a particles of mass 5kg on an inclined plane and it has a force of 20N horizontally?
I'm trying to find the co-efficant of friction, the angle is also tana=3/4

Can someone please explain what i do when i try to solve up the plane and perpendicular to the plane with a horizontal force
Original post by Jowen07
Right so im lost on this question because of the direction of the force, usually these are fairly straight forward but this has thrown me.

What do you do when you have a particles of mass 5kg on an inclined plane and it has a force of 20N horizontally?
I'm trying to find the co-efficant of friction, the angle is also tana=3/4

Can someone please explain what i do when i try to solve up the plane and perpendicular to the plane with a horizontal force

look at the diagram
fafasfsagr.png3.5KB
Reply 2
Avatar for Namod
Namod
10
If tana = 3/4, cosa = 4/5 and sina = 3/5
R = (5g x (4/5)) + (20 x (3/5)) = 59.8
F = μR => μ = F/R

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