You are Here: Home >< Physics

# Help with Edexcel, Physics on the go unit 1 - car problems watch

1. Hey I wonder if anyone could help me, I'm looking at Question 17 from the January 2012 paper and I don't understand how they come to the conclusion for part a) of the initial velocity being more than 10?!?!

Help would be appreciated :-)

P.s to be honest I don't understand the whole question =\
2. (Original post by Branny101)
Hey I wonder if anyone could help me, I'm looking at Question 17 from the January 2012 paper and I don't understand how they come to the conclusion for part a) of the initial velocity being more than 10?!?!

Help would be appreciated :-)

P.s to be honest I don't understand the whole question =\
Could you post the question please?
3. (Original post by limetang)
Could you post the question please?
It's number 17 over here: http://www.edexcel.com/migrationdocu...e_20120307.pdf
4. (Original post by Branny101)
Hey I wonder if anyone could help me, I'm looking at Question 17 from the January 2012 paper and I don't understand how they come to the conclusion for part a) of the initial velocity being more than 10?!?!

Help would be appreciated :-)

P.s to be honest I don't understand the whole question =\
It's a very simple SUVAT question. All you need to do is plug in the proper numbers into the proper equations.
Also, I don't understand what you mean when you say that they 'conclude that the initial velocity is greater than 10'. The conclusion will be the acceleration, not the initial velocity. You get the initial velocity from the graph, if I'm not much in error.
5. What I mean is that if I'm not mistaken the suvat formula you use is "v-u/t" to find the acceleration but in the mark scheme it says that the initial velocity : "u>10" I don't understand how that was found?

If anyone could help me understand where that came from I'd be much obliged :-)

Branny

Posted from TSR Mobile
6. (Original post by Branny101)
What I mean is that if I'm not mistaken the suvat formula you use is "v-u/t" to find the acceleration but in the mark scheme it says that the initial velocity : "u>10" I don't understand how that was found?

If anyone could help me understand where that came from I'd be much obliged :-)

Branny

Posted from TSR Mobile
You can see from the graph that the initial velocity is greater than 10:
7. Right,

Thanks dude! I completely missed the graph in a midst of doing the exam and became confused when I done this question.... Embarrassing

Posted from TSR Mobile

### Related university courses

TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is supported by:
Updated: January 7, 2013
Today on TSR

### He lied about his age

Thought he was 19... really he's 14

### University open days

Wed, 25 Jul '18
2. University of Buckingham
Wed, 25 Jul '18
3. Bournemouth University