The Student Room Group

Implicit differentiate -C4

I am going crazy with this question:

A curve has the equation
x^2 + 3xy -2y^2 + 17 = 0

a) Find an express ion for (dy/dx) in terms of x and y

- This is what I got
2x + 3[x(dy/dx) + y] -4y(dy/dx) =0

hence: dy/dx = (-2x - 3y ) / (3x -4y)

b) Find an equation for the normal to the curve at the point (3, -2)


If i substitue x = 3 y = -2 into the equation grad = 0 hence normal = infinity.
Im pretty sure this is wrong but I can't see where I've made a mistake.
Help appreciated!!
Reply 1
I get the same dy/dx as you.
the normal is therefore x = 3
Reply 2
If i substitue x = 3 y = -2 into the equation grad = 0 hence normal = infinity.
Im pretty sure this is wrong but I can't see where I've made a mistake.
Help appreciated!!
no, your're right , just remember if the gradient is infinity, the line is parallel to the y axis :smile: - so the answer is as YYYY said
Reply 3
ah i c now.
I just generally whenever infinity turns up in an answer i just tend to think its an error. :smile:
Reply 4
If: dy/dx = (-2x - 3y ) / (3x -4y)

subbing x = 3
y = -2
gives 0 as a numerator...?
yeah, so tangent gradient =0 and normal gradient=infinity, and now see my post above and YYYY's
Reply 5
Think of gradient as up/across. so if the gradient is infinity, you're dividing by 0, so the line isnt moving across. Hence must be a vertical line.
Reply 6
when you talk about gradients, you cant say the gradient is infinity. You have to say something like "the denominator is 0, so the gradient tends to infinity making a 90 degree angle with the x-axis, hence the normal/tangent is perpendicular to the x-axis and parallel to the y-axis."
Reply 7
Dev.420
when you talk about gradients, you cant say the gradient is infinity. You have to say something like "the denominator is 0, so the gradient tends to infinity making a 90 degree angle with the x-axis, hence the normal/tangent is perpendicular to the x-axis and parallel to the y-axis."

:hmmmm:
Stick with vertical :p: