Edexcel Chemistry A2 Unit 5 ~ Wednesday 19th June 2013 (Now Closed) Watch

Poll: How pumped up are you for this exam?-(warning)-(bad jokes arene this poll!)
"Titanium-I'm not going to corrode (even at high temperatures)" (A*) (22)
16.67%
"Benzene's my middle name, give me the paper in a week and I'll ace it!" (A) (27)
20.45%
"Yeah, I'm fairly electrophillic (positively charged) about the exam" (B) (27)
20.45%
"I'm in the middle of the salt bridge, but I will pass-eventually" (C) (21)
15.91%
"I'm feeling rather electroNegative about this exam" (D) (18)
13.64%
"Benzene, what's that?" (E) (6)
4.55%
"Chemistry, what's that?" (F) (11)
8.33%
This discussion is closed.
F1's Finest
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#381
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#381
(Original post by NutterFrutter)
Still on gap year. :lol:

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Is this off-topic? :ninja:
noticed you had a neg, I'll pos rep you when I have rep available.
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LeaX
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#382
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#382
This unit is so short. We've almost finished the syllabus already haha.
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jojo1995
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#383
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#383
(Original post by James A)
noticed you had a neg, I'll pos rep you when I have rep available.
sorry it was me I didn't mean it though, sorry nutter, I was just being nosy and trying to click on the spoiler and then ... it happened - sorry again.
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LeaX
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#384
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#384
Hi, everyone.
Is there a way of being able to tell if a reaction is going to be under acidic or alkali conditions? Or is it simply a matter of memorising al the conditions?

Thanks.
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F1's Finest
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#385
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#385
(Original post by LeaX)
Hi, everyone.
Is there a way of being able to tell if a reaction is going to be under acidic or alkali conditions? Or is it simply a matter of memorising al the conditions?

Thanks.
Are you referring to the questions that could pop up in organic chemistry?

Memorise the conditions though.

Like the coupling of benzenediazonium chloride with phenol? That's under alkali conditions, but that's something you have to learn, you will be there for ever trying to justify whether it's under acid or alkali.

There's no shortcuts I'm afraid :no:
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LeaX
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#386
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#386
(Original post by James A)
Are you referring to the questions that could pop up in organic chemistry?

Memorise the conditions though.

Like the coupling of benzenediazonium chloride with phenol? That's under alkali conditions, but that's something you have to learn, you will be there for ever trying to justify whether it's under acid or alkali.

There's no shortcuts I'm afraid :no:
Yep that was what I was referring to. Oh damn it haha, I was hoping there was some easy secret to it or something.
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mkhan51
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#387
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#387
Hi, what product does the following reaction give (this is in preparation for my A2B2 inorganic analysis):
[Zn(H2O)6]2+ + 2OH-

I think it would give: Zn(H2O)4(OH)2 + 2H2O
But someone else said that it is: Zn(H2O)2(OH)2 + 4H2O

Also what is the equation when excess NaOH is added??

Thanks 😀


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F1's Finest
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#388
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#388
(Original post by mkhan51)
Hi, what product does the following reaction give (this is in preparation for my A2B2 inorganic analysis):
[Zn(H2O)6]2+ + 2OH-

I think it would give: Zn(H2O)4(OH)2 + 2H2O
But someone else said that it is: Zn(H2O)2(OH)2 + 4H2O

Also what is the equation when excess NaOH is added??

Thanks 😀


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The product will be Zn(H2O)4(OH)2 + 2H2O, for your first question.

With excess NaOH :

Zn(H2O)4(OH)2 + 4OH- ----> Zn(OH)6 + 4H20
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mkhan51
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#389
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#389
Thanks 😃 Have u done this practical?? Is it hard?? If u have can u give me any tips??


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F1's Finest
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#390
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#390
(Original post by mkhan51)
Thanks 😃 Have u done this practical?? Is it hard?? If u have can u give me any tips??


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I'm not in year 13, I finished my A-levels, but I'm retaking this unit.

I ain't doing the practical as don't attend school no more. (only for the exams I do)
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F1's Finest
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#391
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#391
Got my script back, it's made me realise how careful I need to be with answering questions.

But I've been wrongly done by the examiner here. Lost a mark (I know it's not a big deal, but had i been borderline for the ums I needed for an A, then I would have been well pissed off here).



Question 14d)ii

I wrote 2Cu+ ---> Cu2+ + Cu

Which is correct, but I didn't get a mark for it :sad:

The question even goes on to ask for the electrode potentials, so therefore the answer for ii must be correct for iii to be correct also (which I got two marks for as you can see on the right hand side).

I've uploaded the ms.

The 2+ is fairly clear, but even if it wasn't, I still should have got a mark as I had to use it for the next step.
Attached files
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mkhan51
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#392
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#392
I agree u should have got the mark 😳


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MustaphaMond
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#393
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#393
Do we have to know how to calculate K stability?
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MustaphaMond
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#394
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#394
Also do we have to know about the calomel electrode?
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F1's Finest
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#395
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#395
(Original post by lordmackery)
Also do we have to know about the calomel electrode?
Be aware of it, because in the exam, they could have an experimental question based on the calomel electrode, so although they may not ask questions directly on why it is used over another electrode, it sure will put yourself at ease when you see a question about it, because you've seen that electrode in the textbook and roughly know it's applications.
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jojo1995
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#396
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#396
Does any one know the balanced equation for the formation of phenylamine from nitrobenzene with sn and Hcl ? Please :?
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LeaX
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#397
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#397
I'm dedicating a few days in Easter to go over AS and unit four for the synoptic questions. Do any of you have any suggestions on the main areas to go over? Thanks.
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MustaphaMond
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#398
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#398
I did a question:

The cell represented below was set up under standard conditions

Pt| Fe2+ , Fe3+ || Tl3+, Tl+ |Pt Cell e.m.f. = +0.48V

Use these relevant half equations to write an equation for the spontaneous cell reaction.

Fe3+ + e- -> Fe2+
Tl3+ + 2e- -> Tl+


I wrote:

Tl3+ + 2Fe2+ -> Tl+ + 2Fe3+

is that correct?
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F1's Finest
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#399
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#399
(Original post by lordmackery)
I did a question:

The cell represented below was set up under standard conditions

Pt| Fe2+ , Fe3+ || Tl3+, Tl+ |Pt Cell e.m.f. = +0.48V

Use these relevant half equations to write an equation for the spontaneous cell reaction.

Fe3+ + e- -> Fe2+
Tl3+ + 2e- -> Tl+


I wrote:

Tl3+ + 2Fe2+ -> Tl+ + 2Fe3+

is that correct?
Your half equation for TI3+ + 2e- ---> TI+ is wrong.

Your atoms don't balance right here and hence the charges don't balance.
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David Tennant
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#400
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#400
(Original post by jojo1995)
Does any one know the balanced equation for the formation of phenylamine from nitrobenzene with sn and Hcl ? Please :?
Hey Jojo,

I think this is right! You see, it's reduction of the nitrobenzene to the phenylamine.

C6H5NO2 + 6H+ (in the presence of Sn and HCl)——————→ C6H5NH2 + 2H2O
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