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Thread starter 6 years ago
#1
how would I do Q3ii)

this is what I did

integral of pi(25-x²)
=pi[25x-(1/3)x³] with limits 3 and -3
=pi((75-9)-(-75+9))
=132pi

Have I done something wrong and what do I do next?
0
6 years ago
#2
(Original post by helpme456)
...
As the question says, you need to consider the shaded area as the difference between two areas; and then two volumes.

You've found the volume if you rotate the curve about the x-axis.

Now you need to find the volume of that interior cylinder, and subtract it from the first.

This will give you the required answer.
0
Thread starter 6 years ago
#3
(Original post by ghostwalker)
As the question says, you need to consider the shaded area as the difference between two areas; and then two volumes.

You've found the volume if you rotate the curve about the x-axis.

Now you need to find the volume of that interior cylinder, and subtract it from the first.

This will give you the required answer.
how can I find the interior cylinder volume?
0
6 years ago
#4
(Original post by helpme456)
how can I find the interior cylinder volume?
Refering to your diagram - don't forget the x-axis is the centre of rotation.

And height is ...?

And formula for volume of a cylinder is...?
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Thread starter 6 years ago
#5
(Original post by ghostwalker)
Refering to your diagram - don't forget the x-axis is the centre of rotation.

And height is ...?

And formula for volume of a cylinder is...?
isnt the interior a rectangle though so its volume would be a cuboid not a cylinder
0
6 years ago
#6
(Original post by helpme456)
I thought that another volume of rev had to be done, didnt think of using the equation of volume

r²hpi
=36pi

132pi-2(36pi) = 60pi

STILL not right, what have I done wrong this time
What's your radius and what's your height? Don't forget it's r^2 in there.
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Thread starter 6 years ago
#7
(Original post by ghostwalker)
What's your radius and what's your height? Don't forget it's r^2 in there.
if its the interior we are finding then will the radius be 3 and the height 8

9*pi*8 = 72pi
pi(132-72) = 60pi

the answer should be 36pi

also, why is the volume of cylinder being used, isnt the interior a rectangle?
0
6 years ago
#8
(Original post by helpme456)
if its the interior we are finding then will the radius be 3 and the height 8

9*pi*8 = 72pi
pi(132-72) = 60pi

the answer should be 36pi

also, why is the volume of cylinder being used, isnt the interior a rectangle?
It's a rectangle rotated about the x-axis, giving a cylinder.

The radius is 4, the y value of the straight line at the base of the segment of the circle.

And the height is 3-(-3).
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Thread starter 6 years ago
#9
(Original post by ghostwalker)
It's a rectangle rotated about the x-axis, giving a cylinder.

The radius is 4, the y value of the straight line at the base of the segment of the circle.

And the height is 3-(-3).
How am I supposed to know if the the x part is the radius or the height
0
6 years ago
#10
(Original post by helpme456)
How am I supposed to know if the the x part is the radius or the height
By the fact that the rotation is about the x-axis, as the question says. So the x-axis is the centre, and any line perpendicular to it will be a radius.
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Thread starter 6 years ago
#11
(Original post by ghostwalker)
By the fact that the rotation is about the x-axis, as the question says. So the x-axis is the centre, and any line perpendicular to it will be a radius.
After visualising I can see what you mean. Thanks for sticking at it to make me understand, really appreciated
0
6 years ago
#12
(Original post by helpme456)
After visualising I can see what you mean. Thanks for sticking at it to make me understand, really appreciated
Np. Visualising is a useful technique with some of this "stuff". If only it worked with algebra.
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