# C3 DOubtWatch

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#1
Finding the range of 1 / (2x-1)

In the mark scheme , they are saying: x > 0 ....But I put down x>0 , x cannot equal 0.....Do you think i would be marked wrong:
0
6 years ago
#2
Are you given a domain? I can't decipher your unintelligible sprawl.
1
6 years ago
#3
(Original post by laurawoods)
Finding the range of 1 / (2x-1)

In the mark scheme , they are saying: x > 0 ....But I put down x>0 , x cannot equal 0.....Do you think i would be marked wrong:

isnt that the same thing -so youve written down the right answer
0
6 years ago
#4
(Original post by laurawoods)
Finding the range of 1 / (2x-1)

In the mark scheme , they are saying: x > 0 ....But I put down x>0 , x cannot equal 0.....Do you think i would be marked wrong:
x > 0 implies x =/= 0

So you were redundant, but not wrong. They may dock one mark, but only if they're being particularly harsh.
0
6 years ago
#5
(Original post by laurawoods)
Finding the range of 1 / (2x-1)

In the mark scheme , they are saying: x > 0 ....But I put down x>0 , x cannot equal 0.....Do you think i would be marked wrong:
The range would not be x anything
0
6 years ago
#6
(Original post by laurawoods)
Finding the range of 1 / (2x-1)

In the mark scheme , they are saying: x > 0 ....But I put down x>0 , x cannot equal 0.....Do you think i would be marked wrong:
Are you sure you are looking at the correct answer?

0
6 years ago
#7
(Original post by steve2005)
Are you sure you are looking at the correct answer?

Presumably, the OP means y > 0, and the domain is restricted to x > 0.5
0
6 years ago
#8
(Original post by dendodge)
Presumably, the OP means y > 0, and the domain is restricted to x > 0.5
So many possibilities

Probably this one
1
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