laurawoods
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Finding the range of 1 / (2x-1)

In the mark scheme , they are saying: x > 0 ....But I put down x>0 , x cannot equal 0.....Do you think i would be marked wrong:
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Madalaine M
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Are you given a domain? I can't decipher your unintelligible sprawl.
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MedMed12
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(Original post by laurawoods)
Finding the range of 1 / (2x-1)

In the mark scheme , they are saying: x > 0 ....But I put down x>0 , x cannot equal 0.....Do you think i would be marked wrong:

isnt that the same thing -so youve written down the right answer
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dendodge
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(Original post by laurawoods)
Finding the range of 1 / (2x-1)

In the mark scheme , they are saying: x > 0 ....But I put down x>0 , x cannot equal 0.....Do you think i would be marked wrong:
x > 0 implies x =/= 0

So you were redundant, but not wrong. They may dock one mark, but only if they're being particularly harsh.
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TenOfThem
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(Original post by laurawoods)
Finding the range of 1 / (2x-1)

In the mark scheme , they are saying: x > 0 ....But I put down x>0 , x cannot equal 0.....Do you think i would be marked wrong:
The range would not be x anything
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steve2005
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(Original post by laurawoods)
Finding the range of 1 / (2x-1)

In the mark scheme , they are saying: x > 0 ....But I put down x>0 , x cannot equal 0.....Do you think i would be marked wrong:
Are you sure you are looking at the correct answer?

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dendodge
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(Original post by steve2005)
Are you sure you are looking at the correct answer?

Presumably, the OP means y > 0, and the domain is restricted to x > 0.5
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TenOfThem
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(Original post by dendodge)
Presumably, the OP means y > 0, and the domain is restricted to x > 0.5
So many possibilities

Probably this one
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