# Inz differentiation ofWatch

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#1
If z is a constant is Inz a constant

Anyone?

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0
6 years ago
#2
it's z multiplied by the variable you're integrating with respect to.

e.g. int z dx = zx + c

Wait you do mean ingrate z or do you mean ln(z)?
0
6 years ago
#3
I suspect this is another case of mistaken identity for the natural logarithm.

The natural logarithm of a constant is indeed a constant (so long as the original constant is positive).
0
6 years ago
#4
(Original post by cdoyle)
If z is a constant is Inz a constant

Anyone?

This was posted from The Student Room's iPhone/iPad App
Is there some background to this question?

If z is a constant, then so is f(z) for any function f you may choose
0
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