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Arsey's S1 Edexcel Answers 18th Jan 2013

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Original post by bonjour04
got exactly the same :biggrin:

Congratulationa! :biggrin:
Original post by seana39223
Congratulationa! :biggrin:


to S1 :beer:
Reply 322
91 - A :biggrin:
Original post by EL77
91 - A :biggrin:


Wow, congratulations!!

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Reply 324
Got 86 - but seriously, I have no idea how I got that mark... Did like one or two past papers and I was just playing with numbers for that whole exam.. It felt like I didn't even have a clue what I was doing..
Reply 325
Original post by Padouken
Got 86 - but seriously, I have no idea how I got that mark... Did like one or two past papers and I was just playing with numbers for that whole exam.. It felt like I didn't even have a clue what I was doing..


Wow, was this your first time taking S1 or a re-sit? If it was a re-sit, may i ask what you got before?
Reply 326
My son got 96% but was angry with the poor English/ ambigious meaning of some of the questions. It could have cost him more than it did...
Original post by sj355
My son got 96% but was angry with the poor English/ ambigious meaning of some of the questions. It could have cost him more than it did...


I would be extremely pleased with that!


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Reply 328
Hi, just got a photocopy of my paper back, I got 90 UMS overall (68) but I'm hoping to get higher and looking at the paper for question 4c I got 0 marks but...

I got everything up to p(L>133)=0.0139
and I got 0 marks? Surely that is at least 2 method marks

[This is using Arsey's markscheme]

I didn't get the part about dividing 133 by 127.

Should I get this remarked? I want to get at least 94 UMS, otherwise I will have to retake the paper (since I need to get higher marks in the easy modules so that I can afford mistakes in further maths papers).


Apart from that can someone assess the Katie question answer that I wrote? I only got 1 mark out of 2, may be viable for the full two marks... (thank you for all your help!)
"I would not use normal distribution to model weekly income since the data is positively skewed with a coefficient of 0.757 whilst a normal distribution is symmetrical, i.e. it has no skew.
Also the probability of 240<=y<=400 = 0.52
0.52 calculated via (frequency from 240-400 / Sum of f)
which is quite far from her value of 0.404, showing her model is unreliable.
Therefore Katie's suggestion is bad and wrong. Even here [sic] mean (320) and standard deviation (150) are not the true values of the data which are 316 and 157 respectively, however they are close"
Original post by cyfer
Hi, just got a photocopy of my paper back, I got 90 UMS overall (68) but I'm hoping to get higher and looking at the paper for question 4c I got 0 marks but...

I got everything up to p(L>133)=0.0139
and I got 0 marks? Surely that is at least 2 method marks

[This is using Arsey's markscheme]

I didn't get the part about dividing 133 by 127.

Should I get this remarked? I want to get at least 94 UMS, otherwise I will have to retake the paper (since I need to get higher marks in the easy modules so that I can afford mistakes in further maths papers).


Apart from that can someone assess the Katie question answer that I wrote? I only got 1 mark out of 2, may be viable for the full two marks... (thank you for all your help!)
"I would not use normal distribution to model weekly income since the data is positively skewed with a coefficient of 0.757 whilst a normal distribution is symmetrical, i.e. it has no skew.
Also the probability of 240<=y<=400 = 0.52
0.52 calculated via (frequency from 240-400 / Sum of f)
which is quite far from her value of 0.404, showing her model is unreliable.
Therefore Katie's suggestion is bad and wrong. Even here [sic] mean (320) and standard deviation (150) are not the true values of the data which are 316 and 157 respectively, however they are close"


On the official mark scheme you have to use the conditional part of the question to get the marks, which is annoying! How much did it cost to get your script back?


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Reply 330
Original post by pilotluke1
On the official mark scheme you have to use the conditional part of the question to get the marks, which is annoying! How much did it cost to get your script back?


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£10

Please can you link me the official mark scheme?
Original post by cyfer
can someone assess the Katie question answer that I wrote? I only got 1 mark out of 2, may be viable for the full two marks... (thank you for all your help!)
"I would not use normal distribution to model weekly income since the data is positively skewed with a coefficient of 0.757 whilst a normal distribution is symmetrical, i.e. it has no skew.
Also the probability of 240<=y<=400 = 0.52
0.52 calculated via (frequency from 240-400 / Sum of f)
which is quite far from her value of 0.404, showing her model is unreliable.
Therefore Katie's suggestion is bad and wrong. Even here [sic] mean (320) and standard deviation (150) are not the true values of the data which are 316 and 157 respectively, however they are close"


The question requires that you comment on the answer you found to part d that shows the data is skewed so normal is not appropriate (1 mark) but also part e and the table that shows a normal distribution over that range would predict the same probability that you observe looking at the data in the table which suggests a reasonable fit for this range. (1 mark)
(edited 11 years ago)
Reply 333
Yeah look like I'm not getting any extra marks, I won't remark.

I wonder if that 4c question was what everybody screwed up on - highest mark in my class was 94 (I was second) so I'm guessing that was the question everyone dropped marks on.
Original post by cyfer
Yeah look like I'm not getting any extra marks, I won't remark.

I wonder if that 4c question was what everybody screwed up on - highest mark in my class was 94 (I was second) so I'm guessing that was the question everyone dropped marks on.


From the papers I've reviewed with students
4c (4 marks) - missing the conditional probability
5f (2 marks) - commenting only on skewness, ignoring the part e and that data in the table
6f (4 marks) - not picking up that she can choose either dice depending on the outcome of the coin toss

Think students may have got used to the predictability of past S1 papers.
Reply 335
Original post by gdunne42
From the papers I've reviewed with students
4c (4 marks) - missing the conditional probability
5f (2 marks) - commenting only on skewness, ignoring the part e and that data in the table
6f (4 marks) - not picking up that she can choose either dice depending on the outcome of the coin toss

Think students may have got used to the predictability of past S1 papers.


I can understand the second two, but normal distribution AND conditional probability in one question? I've never seen nor done an example of that.
Original post by cyfer
I can understand the second two, but normal distribution AND conditional probability in one question? I've never seen nor done an example of that.

Agreed, after some criticism that papers are too predictable (and that some papers can be done just by crunching numbers through formulae with little understanding) I think they are injecting a little bit more 'thinking' challenge to test the more capable candidates.
Reply 337
Original post by gdunne42
Agreed, after some criticism that papers are too predictable (and that some papers can be done just by crunching numbers through formulae with little understanding) I think they are injecting a little bit more 'thinking' challenge to test the more capable candidates.


Haha since when was thinking required? :frown:

I wish they'd just leave all that hush to FP1+
Original post by gdunne42
From the papers I've reviewed with students
4c (4 marks) - missing the conditional probability
5f (2 marks) - commenting only on skewness, ignoring the part e and that data in the table
6f (4 marks) - not picking up that she can choose either dice depending on the outcome of the coin toss

Think students may have got used to the predictability of past S1 papers.


Hi I got 86 however, I feel like I should have got a few extra marks! I looked @ the official mark scheme and I only counted losing 7 marks in total: 1 from the Katie question is I only talked about the data being skewed....4 from the conditional normal distribution question and 2 for getting the last question wrong. A UMS mark of 86 means that I only got 65/75 and lost 10 marks so I'm not 2 sure why how and where I lost the other 3.
Is it worth getting a remark done? Is the Ear1 process an actual remark of paper or simply the marks being added up again?
Reply 339
I got 68/100 which was a C thanks to stupid mistakes :/ Will be resitting in summer :smile:


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