DoeADeer
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Report Thread starter 6 years ago
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Hi there.
I'm having a bit of trouble with question 5b. I did 5a and got 9P5 = 15120.

For b I did [(8P4 x 2!) + 7P3]÷15120 but the answer is 5/6.

I don't have a clue how to so part c.
Please help
Thanks!

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TenOfThem
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Report 6 years ago
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5(a) Should be 9C5

5(b) Neither chosen would be 7C5 ... can you see how to use this
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DoeADeer
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Report Thread starter 6 years ago
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(Original post by TenOfThem)
5(a) Should be 9C5

5(b) Neither chosen would be 7C5 ... can you see how to use this
The answers say to use P. I thought it was a bit difficult to determine whether it was combination or permutation.
Oh yeah, so the previous answer take away 7P5. Thanks!

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TenOfThem
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(Original post by DoeADeer)
The answers say to use P.
Yes, I was thinking of just filling the seats

But ABCDE would be a different way of filling the seats to ABCED
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