Maths Problem Watch
How can DB=CD=EB, surely CD>EB
Can we please see the original question?
The question as stated can be solved. What's the problem you see with it?
The diagram is clearly not very good because E looks to be vertically above D but this can't be correct because that would mean the hypotenuse of triangle EDB was equal to the side DB.
The OP has indicated that some angles are right angles BUT this information is not included in the description.
Prove that angle CDA is twice angle CBA.
As for finding AD