AminKhan
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Any Ideas into how to solve this...Name:  ImageUploadedByStudent Room1358724250.947184.jpg
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BabyMaths
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A combination of Pythagoras and similar triangles lead me to an ugly equation. The answer is about 0.2599 I think.
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BabyMaths
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To be more precise it's 2^{1/3}-1
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steve2005
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I don't think the diagram can be correct.

How can DB=CD=EB, surely CD>EB

Can we please see the original question?
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123formyabc
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(Original post by steve2005)
I don't think the diagram can be correct.

How can DB=CD=EB, surely CD>EB

Can we please see the original question?
I was thinking the same
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BabyMaths
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(Original post by steve2005)
I don't think the diagram can be correct.

How can DB=CD=EB, surely CD>EB

Can we please see the original question?
CD=DB=EB=1. That's what the question says so how can you suggest that CD>EB?
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steve2005
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(Original post by BabyMaths)
CD=DB=EB=1. That's what the question says so how can you suggest that CD>EB?
I think the OP has made a mistake, simple.
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BabyMaths
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(Original post by steve2005)
I think the OP has made a mistake, simple.
The question as stated can be solved. What's the problem you see with it?
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steve2005
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(Original post by BabyMaths)
The question as stated can be solved. What's the problem you see with it?
Perhaps you're right, perhaps you're wrong.

The diagram is clearly not very good because E looks to be vertically above D but this can't be correct because that would mean the hypotenuse of triangle EDB was equal to the side DB.

The OP has indicated that some angles are right angles BUT this information is not included in the description.
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BabyMaths
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It's just a sketch. The appearance of the sketch is not important. What is important is the precise information given.
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AminKhan
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The sketch is not mine. I literally found it like this...and I do agree that it does not make sense but the diagram is just not drawn to proportion, but it still can be worked out.


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BabyMaths
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A nice extra problem is:

Prove that angle CDA is twice angle CBA.

As for finding AD

Spoiler:
Show


Pythagoras and similar triangles lead to the equation

(x+1)^4=(x+1)^2+1-x^2

Dividing by x+1 leads quickly to the solution.

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