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    Here is the question, I'm puzzled as for part A I got -4.92, but you cant get a negative angle!

    Please help

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    Link to question: http://gyazo.com/08d6f88cb5292282f53663f0b8bff528
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    Think you need to show that piece of working!
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    (Original post by Mr M)
    Think you need to show that piece of working!
    I'm using 1/2r^2Q (Q= theta)

    0.5(9.2^2)Q=37.4
    Q= 37.4 - 42.32
    Q= -4.92
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    (Original post by User32432432)
    I'm using 1/2r^2Q (Q= theta)

    0.5(9.2^2)Q=37.4
    Q= 37.4 - 42.32
    Q= -4.92
    Oh dear.

    Your first line is correct.

    ax=b

    does not lead to

    x=b-a
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    (Original post by Mr M)
    Oh dear.

    Your first line is correct.

    ax=b

    does not lead to

    x=b-a
    Oh my dear lord, Just realised what I missed, feel stupid lol.
    Thanks
    Did you get 0.89 Rad ?
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    try solving the equation first for \theta

    to get: \theta=\frac{2A}{r^2}

    then plug the values in
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    (Original post by User32432432)
    Oh my dear lord, Just realised what I missed, feel stupid lol.
    Thanks
    Did you get 0.89 Rad ?
    0.8837429 (although difference is tenths of an angle [in degrees])
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    (Original post by Hasufel)
    0.8837429
    Yea, good I rounded it up 2 sig fig
 
 
 
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