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High or low spin complex from magneic moment Watch

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    How do I determine whether [Cr(en)3]2+ is high or low spin knowing that the magnetic moment of it is 4.84 BM?

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    (Original post by DonnieBrasco)
    How do I determine whether [Cr(en)3]2+ is high or low spin knowing that the magnetic moment of it is 4.84 BM?

    Thanks

    Can't remember much of magnetochemistry but for Cr2+ complexes, 4.84 BM is consistent with 4 unpaired electrons, meaning it is high-spin.

    Table of values here:

    http://en.wikipedia.org/wiki/Magneto..._of_metal_ions

    Sorry I can't be of further help!
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    (Original post by DonnieBrasco)
    How do I determine whether [Cr(en)3]2+ is high or low spin knowing that the magnetic moment of it is 4.84 BM?

    Thanks
    Use the spin only formula to deduce the number of unpaired electrons.
    Then calculate the number of d electrons on your Cr atom.
    Put them into the octahedral splitting arrangement (t2g and eg)
    Try both high and low spin, see which one has the number of unpaired electrons you calculated earlier.
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    Ahh ok, Thanks!
 
 
 
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