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# need help with an assignment watch

1. If a certain number of two digit be divided by the sum of the digits, the quotient is 2 and the remainder 8.Three times the given number is 2 greater than the number expressed by the digit in reversed order. What is the number?
2. Some hints for you:

Let the two digits (from left to right) be a and b.

Then the number formed is given by 10a+b

Since this number when divided the sum of the digits yield a quotient of 2 and a remainder of 8,

then we have (10a+b)/(a+b)= 2 + 8/(a+b) =======> 10a+b = 2(a+b) +8 ----------(1)

Based on the second set of information provided in the problem, formulate a separate equation relating a and b similar to (1), before proceeding to solve things simultaneously.

Hope this helps. Peace.

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Updated: March 8, 2013
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