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    (Original post by MasterYi)
    Correct, I guess that was straight out of you head or text book


    straight from my head

    Define:aromatic
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    (Original post by otrivine)
    straight from my head

    Define:aromatic
    Smells.
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    (Original post by MasterYi)
    Smells.
    No! come on!

    Its any compound that contains one or more benzene ring.
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    (Original post by otrivine)
    No! come on!

    Its any compound that contains one or more benzene ring.
    Ohright you mean that definition! I was genuinely wondering why you asked that.

    One more question for you and I'm going to sleep.

    What is Condensation Polymerisation​?
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    (Original post by MasterYi)
    Ohright you mean that definition! I was genuinely wondering why you asked that.

    One more question for you and I'm going to sleep.

    What is Condensation Polymerisation​?
    Is the process in which two monomers react to form a long polymer chan by the removal of small molecules such as water and HCL to form a long polymer chain of repeat unit.
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    (Original post by otrivine)
    Is the process in which two monomers react to form a long polymer chan by the removal of small molecules such as water and HCL to form a long polymer chain of repeat unit.
    Yes, but where did you get the 'removal of HCL' part from?
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    (Original post by MasterYi)
    Yes, but where did you get the 'removal of HCL' part from?

    from the end of the chain
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    (Original post by otrivine)
    from the end of the chain
    I meant where in the texts books/modules etc.

    Although I still don't understand why there is HCL being removed.
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    (Original post by MasterYi)
    I meant where in the texts books/modules etc.

    Although I still don't understand why there is HCL being removed.
    In the book they never show an example with the removal of HCL but I am assuming that if you see a H on one side of the compound and a Cl on the other end side of compound you remove the HCL and join the two monomers together?
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    (Original post by otrivine)
    In the book they never show an example with the removal of HCL but I am assuming that if you see a H on one side of the compound and a Cl on the other end side of compound you remove the HCL and join the two monomers together?
    Hmmm. We only deal with amino acids and their condensation reactions.

    And when two two amino acids undergo condensation polymerisation, a water molecule is released and a peptide linkage is formed.

    So in theory, there shouldn't be any H's or Cl's hanging around because you're always joining the carboxyl group with the amino group.

    Unless you're talking about something which I don't know about, then feel free to explain and I'll read tomorrow.

    EDIT: OH crap, I've just mixed up two things. Ooops, I'm tired. Forget everything I said!
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    (Original post by MasterYi)
    Hmmm. We only deal with amino acids and their condensation reactions.

    And when two two amino acids undergo condensation polymerisation, a water molecule is released and a peptide linkage is formed.

    So in theory, there shouldn't be any H's or Cl's hanging around because you're always joining the carboxyl group with the amino group.

    Unless you're talking about something which I don't know about, then feel free to explain and I'll read tomorrow.
    I agree with you, but then why the book says HCL? :confused:
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    (Original post by otrivine)
    I agree with you, but then why the book says HCL? :confused:
    Don't quote me on this but isn't it because when forming a polyester you're reacting an alcohol with a carboxylic acid, in the same way you can react an alcohol with an acid chloride to make the polyester where the small molecule that is removed would be HCL.

    I've never seen a question about it yet though.


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    (Original post by otrivine)
    In the book they never show an example with the removal of HCL but I am assuming that if you see a H on one side of the compound and a Cl on the other end side of compound you remove the HCL and join the two monomers together?
    Yes. You are right. Think of the reaction between an amine and and acyl chloride. You produce an amide and HCl
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    Does anyone have or know where I can get the January 2013 papers for
    F324: Rings, Polymers and Analysis
    F325: Equilibria, Energetics and Elements

    Thankyou

    and the mark schemes if possible please!
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    (Original post by otrivine)
    I agree with you, but then why the book says HCL? :confused:
    i am also sitting this exam , want to revise?
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    (Original post by Zzzyax)
    i am also sitting this exam , want to revise?
    sure

    lets do chapters 1 and 2
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    (Original post by otrivine)
    sure

    lets do chapters 1 and 2

    have you not finished chapter 3 yet?

    what is a zwitterion?

    What is the reagents/catalysts/ conditions for

    1) bromination of benzene
    2)bromination of phenol
    3)Nitration of benzene
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    (Original post by Zzzyax)
    have you not finished chapter 3 yet?

    what is a zwitterion?

    What is the reagents/catalysts/ conditions for

    1) bromination of benzene
    2)bromination of phenol
    3)Nitration of benzene


    1) Zwitterion is a dipolar ionic form of an amino acid and the donation of H+ from the carboxyl group to the amino group and results in both charges being present and as a result the overall charge cancels out.

    2) halogen carrier is needed and takes place at room temperature in the dark.
    halogen carrier
    mxture of concentrated h2so4 and HNO3 and takes place at 50 degrees, you would also need a condenser
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    The oxidation of an aldehyde to a ketone doesn't produce water does it?
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    (Original post by fletchdd02)
    The oxidation of an aldehyde to a ketone doesn't produce water does it?
    You can't oxidise an aldehyde to a ketone if I remember correctly.

    It's primary alcohol can be oxidised to an aldehyde with the use of acidified potassium dichromate and a sulphuric acid catalyst which is then distilled or can be oxidised through reflux to a carboxylic acid, both with a molecule of water being released. At least this is what I know so I'm not 100% sure it's correct.


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