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    (Original post by thers)
    Anyone want to revise?
    Yeah man go for it.

    Why are triglycerides not soluble in water?
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    can anyone help me with the jan 2010 paper qs 5d

    http://www.ocr.org.uk/Images/65129-q...d-analysis.pdf

    thanks
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    Sorry to be a pain but somebody posted some word documents consisting and questions and answers for different topics and I can't find them.... Total respect for anyone who can tell me the page number on the thread which has these documents
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    (Original post by Mus1995)
    Yeah man go for it.

    Why are triglycerides not soluble in water?

    Triglycerides are non polar so cannot interact with polar water molecules (via hydrogen bonding) so are hydrophobic.

    Turns out I've got to go now for a while - shouldn't have bothered saying who want to revise now.

    I will give you a Q before I go tho

    Define the term biodegradable polymer. [1]
    Suggest two reasons why biodegradable polymers are inreasing in importance. [2]
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    (Original post by rukan)
    can anyone help me with the jan 2010 paper qs 5d

    http://www.ocr.org.uk/Images/65129-q...d-analysis.pdf

    thanks
    Look at the functional group attached to the benzene ring tha should give you an insight into the question. One has a carboxy group and other has oh group which is a phenol so with both naoh or na can bond. Only asprin na2co3 and only phenol 3br2
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    (Original post by Raj Kang)
    For nh2 and oh groups these are singlets because they have no adjacent protons by the n+1 rule. Splitting can only occur on adjacent protons, so the next carbon which has protons attached. If no protons are on adjacent carbons on ether side then that specific type of proton is going to be a singlet
    Isn't the amine group in methionine attached to a carbon with a proton attached, though? So why isn't it a doublet? Sorry, my quote apparently didn't include the attachment. It was Q3 e iii on the Jan 13 paper.
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    (Original post by thers)
    Triglycerides are non polar so cannot interact with polar water molecules (via hydrogen bonding) so are hydrophobic.

    Turns out I've got to go now for a while - shouldn't have bothered saying who want to revise now.

    I will give you a Q before I go tho

    Define the term biodegradable polymer. [1]
    Suggest two reasons why biodegradable polymers are inreasing in importance. [2]
    Correct.

    It's alright.

    A biodegradable polymer is a polymer that breaks down completely into Carbon Dioxide and Water.

    Increased importance due to rising oil prices and need for reusable plastics. Biodegradable plastics can be recycled and reused.
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    (Original post by Raj Kang)
    Look at the functional group attached to the benzene ring tha should give you an insight into the question. One has a carboxy group and other has oh group which is a phenol so with both naoh or na can bond. Only asprin na2co3 and only phenol 3br2
    thanks.. but aspirin and paracetamol both have a carbonyl group so why does the paracetamol only react with br2?
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    (Original post by rukan)
    thanks.. but aspirin and paracetamol both have a carbonyl group so why does the paracetamol only react with br2?
    Becuase paracetamol has phenol group and can decolourise orange bromine water and asprin had benze ring attached to carboxyl and cannot hence asprin does no react with br2
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    (Original post by wl1)
    Isn't the amine group in methionine attached to a carbon with a proton attached, though? So why isn't it a doublet? Sorry, my quote apparently didn't include the attachment. It was Q3 e iii on the Jan 13 paper.
    Think of it like this, groups that have nh2 or oh attached are always going to have splitting pattern of singlet. This is because it has to be adjacent to proton on the next carbon atom
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    Any predictions what is going to come up?
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    (Original post by Raj Kang)
    Becuase paracetamol has phenol group and can decolourise orange bromine water and asprin had benze ring attached to carboxyl and cannot hence asprin does no react with br2
    oh okkk i get you now thanks
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    (Original post by D4rth)
    Well you've got 21 hours remaining. Ideally you should've completed all the past papers.
    I would read over the specification, if there is something you don't know go and learn it quickly.

    Posted from TSR Mobile
    I have finished all of them. I'm going to do them again.
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    is there a formula or way of deducing how many isomers a compound would have or is it just a matter of actually drawing it out?
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    Any Predictions?
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    Here are the January 2013 papers for F324.
    Attached Images
  1. File Type: pdf F324 January 2013.pdf (229.1 KB, 71 views)
  2. File Type: pdf F324 January 2013 MS.pdf (268.6 KB, 52 views)
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    (Original post by Nuna)
    help...I really don't understand the mark scheme for Q4ai and 4aii on the January 2011 paper??
    .....anyone ?
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    Brady's reagent = 2,4-dnp?
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    How many substitutions could take place on Benzene ring? could it be all 6? So could you end up with C6H6 --> C6(NO2)6?? as an example?
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    (Original post by ofudge)
    How many substitutions could take place on Benzene ring? could it be all 6? So could you end up with C6H6 --> C6(NO2)6?? as an example?
    I don't know but the more groups on the benzene ring the harder it will be for another group to bond to it.
 
 
 
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