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# OCR Chemistry F322~ 4th June 2013~ AS Chemistry watch

• View Poll Results: How did you find the exam
Hard A= 72
42
15.22%
It was okay A= 76
99
35.87%
Easy A= 79
75
27.17%
Very Easy A=82
60
21.74%

1. (Original post by redtortoise)
Iput c-o and c=o but was really confused, I did put c=c first but got muddled
I put the same, think you would still get a mark for c=o rather than ester
2. (Original post by Dizzie31)
correct.
the answer is 1640, 240/20= 10 moles 10x 164 to give 1640
3. (Original post by jacksonmeg)
I put alkene and carbonyl, will that count ?
a ketone is a carbonyl, but i'm not 100% sure whether it would be accepted
4. Could anyone upload the paper itself or the unofficial mark scheme?
5. (Original post by _Morsey_)
Are you referring to that one with above 2.5 atmospheric pressure etc? For both i put it to shift left, with absence of catalyst slowing down the rate at which dynamic equilibrium is reached.

Well it asked for two propagation stages, so i did;

Initiation: IBr -> I. + Br.

Propagation Step 1: CH4 + Br. > CH3. + HBr
Propagation Step 2: CH3. + I2 > CH3I + I.

Termination: Br + I > IBr etc.

Thats what i did so i hope it is right :3

Where does the I2 come from?

I got

Initiation: IBr -> I. + Br.

Propagation Step 1: CH4 + Br. > CH3. + HBr
Propagation Step 2: CH3. + IBr > CH3I + Br.
6. (Original post by massi1296)
the answer is 1640, 240/20= 10 moles 10x 164 to give 1640
There was 2 moles already in the original equation, not 1.
10/2 = 5
so you times it by 5.
7. For the answer after 820, was it 82?
8. (Original post by daisyrchds)
same! seriously need to brush up on my octagon drawing skills though, re-drew it like 4 times
i couldnt draw a branched 10 C alkane, took me 4 times to get the right amount of C ._.
9. i put ester c-o and alkene c=c
10. You can't just predict the Grade boundaries.. I know quiet a few people in my class who hates the paper if you thought it was easy you can't generalise tens of thousands who sat this paper lol
11. (Original post by dawg)
Where does the I2 come from?

I got

Initiation: IBr -> I. + Br.

Propagation Step 1: CH4 + Br. > CH3. + HBr
Propagation Step 2: CH3. + IBr > CH3I + Br.
i wrote that^
12. (Original post by Liberty.)
Please tell me people just drew an octagon on the second page? I felt like an idiot
i tried to but my octagon ended up more like a circle, so i redrew the cyclooctane putting CH2 at each corner just to emphasise what shape it was supposed to be :L
13. (Original post by irfymahmood)
yeppp i did
There was also a ridiculously small amount of room to draw an ester, with a carbon ring in it, in a puny box.
14. (Original post by jacksonmeg)
I put alkene and carbonyl, will that count ?
I wouldn't think you would get it for carbonyl
15. (Original post by kingmango)
For the answer after 820, was it 82?
yeah 164 / 2 i think
16. (Original post by Dizzie31)
There was 2 moles already in the original equation, not 1.
10/2 = 5
so you times it by 5.
isnt it /24 not /20 ?
17. (Original post by dawg)
Where does the I2 come from?

I got

Initiation: IBr -> I. + Br.

Propagation Step 1: CH4 + Br. > CH3. + HBr
Propagation Step 2: CH3. + IBr > CH3I + Br.

Yeh, i'm not quite sure why i put I2...
18. (Original post by Dizzie31)
There was 2 moles already in the original equation, not 1.
10/2 = 5
so you times it by 5.
the +164 was for 2 moles of the N20 formed so you didnt have to divide by 2
19. (Original post by jacksonmeg)
isnt it /24 not /20 ?
the volume was 240
240/24 = 10
10/2 = 5 .. Mole ratio
5 x 164 or whatever = answer
20. (Original post by Dizzie31)
yeah 164 / 2 i think
Sweeeet.
I'm thinking 82 for an A?

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