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OCR Chemistry F322~ 4th June 2013~ AS Chemistry Watch

  • View Poll Results: How did you find the exam
    Hard A= 72
    42
    15.22%
    It was okay A= 76
    99
    35.87%
    Easy A= 79
    75
    27.17%
    Very Easy A=82
    60
    21.74%

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    (Original post by haidaralinasir)
    you're ****ed.
    Don't swear at me please.
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    14
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    (Original post by RebelV005)
    Hold on chemistss

    it had to be butanal as the molecular formula would not be appropriate for butaone.

    Try drawing butaone
    Brother it said 2 products

    Aldehyde and butanone have sme molecular formula
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    (Original post by RebelV005)
    Hold on chemistss

    it had to be butanal as the molecular formula would not be appropriate for butaone.

    Try drawing butaone
    Yes it would..... CH3CH2COCH3 is the same as CH3CH2CH2CHO
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    Can somebody add a voting chart please.
    So we can know how others found it
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    (Original post by Kat12395)
    Urk, if I spelled breathalysers wrong will I get the mark?:L


    Posted from TSR Mobile
    You just spelt it right. It is spelt 'breathalysers'. So if you spelt it like that in the exam then you're fine!
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    (Original post by kenna)
    yup, at least 80 for an a i reckon.
    fock off pikey w@nk3r!!!!! Th4t was the fockin hardest paper ive ever dun! Stop acting like a ****ing god
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    (Original post by yodawg321)
    For the flame question on why it was a yellow or blue flame

    I put its because there's a supply of oxygen so it's an complete combustion so gas is being produced (Co2)

    For people who put incomplete combustion I don't understand how because Incomplete releases Carbon Monoxide and its a colourless gas :s
    Hmm I said because CO2 gas is being produced. Reacon I'll get a mark for that?
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    (Original post by wndms)
    Exactly what I got! I got confused so I wrote a mechanism for HBr which was easier, then replaced H with I...

    Posted from TSR Mobile
    Wait, wait, I'm confused on this question.

    I put:

    Initiation: IBr -> I∙ + Br∙
    Prop1: CH4 + Br∙ -> CH3∙+ HBr
    Prop2: CH3∙+ I2-> CH3I + I∙
    Termination/Overall (Can't remember): CH4 + IBr -> HBr + CH3I

    (I hope)
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    For the question about the enthalpy change for 240dm^3 of NO2, I put +820 (thereabouts), because 240dm^3 was 10 moles, and we were given the enthalpy change for 2N2+O2 -> 2NO2, which was +164. Is this correct?
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    is there a range for temps for the fermentation process? i put 30

    also will they allow breath analyser instead of breathylyser? i was so certain breathalyser was not a word
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    ehh this thread is awful so many speculative posts
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    (Original post by TheFootyKing19)
    Yeah!

    Marking points will be:

    - Radical Substitution
    - Homolytic Fission
    - names of 2 steps = initiation and propagation
    - termination step equation (any)

    That's 4 marks:
    And other 3 marks will be for the 3 equations
    "Free Radical Substitution" - accepted?
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    (Original post by RebelV005)
    Hold on chemistss

    it had to be butanal as the molecular formula would not be appropriate for butaone.

    Try drawing butaone
    It would be appropriate, whats your point?
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    (Original post by alice.o123)
    couldn't have been a carboxylic acid because the empirical formula meant there was only one oxygen atom present in the molecule M and a carboxylic acid has two oxygen atoms (COOH), it was either a ketone or an aldehyde as both can have the same molecular formula (and Mr) since they are structural isomers and contain only one oxygen atom and a C=O group.
    now I dont remember the question properly need to look at the mark scheme
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    (Original post by the A* guy)
    i am trying to upload the first 5 pages now, But it is taking AGES.
    Is it? Well, at least the scanner worked!!
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    (Original post by Felttip)
    fock off pikey w@nk3r!!!!! Th4t was the fockin hardest paper ive ever dun! Stop acting like a ****ing god
    Compared to other papers it was slightly easier, I'm not saying the paper itself was easy it is an A level paper, meant to be difficult.
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    (Original post by nothepreacher)
    hey do you know what the molecular formula of alcohol g was?
    C4H9OH or C4H10O I think
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    (Original post by nothepreacher)
    hey do you know what the molecular formula of alcohol g was?
    Naming an alcohol (first few pages)
    - 3-methylpentan2-ol

    And was molecular formula of G:
    C6H12O

    Wasn't it?
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    (Original post by Saif95)
    Is it? Well, at least the scanner worked!!
    im getting this 503 error thing when i try to upload it
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    For the IR question, I did two aldehydes, one straight chained and one branched. Do you think that's fine?
 
 
 
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