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OCR Chemistry F322~ 4th June 2013~ AS Chemistry Watch

  • View Poll Results: How did you find the exam
    Hard A= 72
    42
    15.22%
    It was okay A= 76
    99
    35.87%
    Easy A= 79
    75
    27.17%
    Very Easy A=82
    60
    21.74%

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    (Original post by Monkeys!)
    A little bit late, but thank you SOOOOOOOOO much!
    its alright
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    (Original post by jazzynutter)





    Alkane → CO2 + H2O
    Alkane → Halogenoalkane
    Alkane → Alkane + Alkene
    Alkane → Cycloalkane
    Alkane → Branched Alkane
    Alkene → CO2 + H2O
    Alkene → Monohalogenated alkane
    Alkene → Dihalogenated alkane
    Alkene → Alkane
    Alkene → Alcohol
    Alkene → Poly(Alkene)
    Alcohol → CO2 + H2O
    Alcohol → Ester
    Alcohol → Aldehyde
    Alcohol → Carboxylic Acid
    Alcohol → Ketone
    Alcohol → Alkene
    Glucose → Alcohol
    Halogenoalkane → Alcohol
    Halogenoalkene → Poly(Halogenoalkene)

    Ta-daaaaa!
    Fabb! Thank you! There are far too many reactions to learn!
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    (Original post by jazzynutter)
    I know this because I used to make the same mistake on every single past paper..... for example, the oxidation product the last time I made this mistake was CH3CH2CH2COOH, and on the right hand side it specifically said not to accept C3H7COOH. These particular equations are always two marks, so I was limited to one because of that.
    how comes you decided to oxidise it to an acid, did you not see if the question said reflux or distil? or did you just assume they would all go to acid?
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    (Original post by needtosucceed=))
    yep you would, you asked me this yesterday as well, you probably missed the quote lol
    Haha sorry, probably because so many people were posting I didn't see it. Thanks anyway


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    (Original post by Jimmy20002012)
    Haha sorry, probably because so many people were posting I didn't see it. Thanks anyway


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    lol no problem
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    do we have to knw how the apparatus is set up for the oxidation of primary alcohols into aldehydes and carboxylic acids?
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    (Original post by junaid_k17)
    do we have to knw how the apparatus is set up for the oxidation of primary alcohols into aldehydes and carboxylic acids?
    Not how it works, just to know distillation and reflux for particular oxidation of alcohols


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    (Original post by needtosucceed=))
    yep you would, you asked me this yesterday as well, you probably missed the quote lol
    anyone have the jan 2013 paper and mark scheme?
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    Can someone please help me with steroisomers? question 3iv on jan 13 paper??
    THANKS IN ADVANCE
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    GUYS please help... i don't get isomers.. of alkenes specially the ones they genrally ask like even in Jan 2013 and Jan 2012 papper

    5dii <----Jan 12
    3a iv <----Jan 13

    THANK YOU VERY MUCH
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    (Original post by needtosucceed=))
    how comes you decided to oxidise it to an acid, did you not see if the question said reflux or distil? or did you just assume they would all go to acid?
    My point is that both of those formulae technically represent exactly the same thing, but they needed to see the structural formula to see that you fully understood where the functional group went! (The question was reflux of a primary alcohol)
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    (Original post by Legal drugdealer)
    anyone have the jan 2013 paper and mark scheme?
    I have added it in the OP


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    (Original post by Cerelaaa)
    Fabb! Thank you! There are far too many reactions to learn!
    Alkene can form co2 + H2o???? :confused:
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    (Original post by Sum786)
    Can someone please help me with steroisomers? question 3iv on jan 12 paper??
    THANKS IN ADVANCE

    LOL that's what i put up lloll a the same time as you
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    (Original post by Jacksgap)
    Alkene can form co2 + H2o???? :confused:
    I think that's just referring to combustion

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    (Original post by Sum786)
    Can someone please help me with steroisomers? question 3iv on jan 12 paper??
    THANKS IN ADVANCE
    theres no 3iv on the paper?
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    (Original post by jazzynutter)
    My point is that both of those formulae technically represent exactly the same thing, but they needed to see the structural formula to see that you fully understood where the functional group went! (The question was reflux of a primary alcohol)
    ohh sorry yea I see what you mean, i've done that before too. but I dont' see why c3h7cooh is any different to writing the whole thing out, because it still shows exactly where your functional groups present. but yea best just to write the whole structure out
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    (Original post by needtosucceed=))
    theres no 3iv on the paper?
    3 A iv I asked the same question too

    Thanks genius in advance
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    (Original post by Jacksgap)
    Alkene can form co2 + H2o???? :confused:
    Complete combusion...

    so CH4 + 2O2 -> CO2 + 2H2O.
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    (Original post by Cerelaaa)
    Complete combusion...

    so CH4 + 2O2 -> CO2 + 2H2O.
    You said Alkene.. if i am not mistaken..
 
 
 
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