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OCR Chemistry F322~ 4th June 2013~ AS Chemistry Watch

  • View Poll Results: How did you find the exam
    Hard A= 72
    42
    15.22%
    It was okay A= 76
    99
    35.87%
    Easy A= 79
    75
    27.17%
    Very Easy A=82
    60
    21.74%

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    Also can someone please explain the major points of green chemistry?


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    (Original post by beautywithbrains)
    Which had been the hardest paper so far?


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    jan 2011 had the lowest boundary for an A, 71
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    Hey can anyone explain how to do question 1(e)(iii) from the june 2010 paper?
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    (Original post by beautywithbrains)
    Also can someone please explain the major points of green chemistry?


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    past papers and mark schemes are the best thing to look at for green chemistry
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    Also does anyone know why for June 10 paper 1(e)(v) it asks to comment on percentage yield and atom economy but then on mark scheme it says 'ignore comments on percentage yield'?!!
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    (Original post by needtosucceed=))
    past papers and mark schemes are the best thing to look at for green chemistry
    Ok thanks!


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    (Original post by needtosucceed=))
    moles is mass/molar mass
    so 3.6x10^5/26
    but it says 3.6x10^5 dm3 made each day not grams?
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    (Original post by lucy3003)
    Hey can anyone explain how to do question 1(e)(iii) from the june 2010 paper?
    your given the volume of c2h2 so number of moles = volume/24

    so 3.6x10^5/24 = 15000
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    (Original post by lucy3003)
    but it says 3.6x10^5 dm3 made each day not grams?
    sorry ignore that post.
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    (Original post by needtosucceed=))
    your given the volume of c2h2 so number of moles = volume/24

    so 3.6x10^5/24 = 15000
    Ooohhh yes of course thank you!!
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    (Original post by lucy3003)
    Also does anyone know why for June 10 paper 1(e)(v) it asks to comment on percentage yield and atom economy but then on mark scheme it says 'ignore comments on percentage yield'?!!
    yea i was wondering this too, pretty stupid really
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    Anyone mind helping me with this question about determining displayed formulas of organic compounds; 2 (e) http://www.ocr.org.uk/Images/131287-...-resources.pdf

    MS: http://www.ocr.org.uk/Images/135164-...urces-june.pdf
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    (Original post by Daniel__)
    Anyone mind helping me with this question about determining displayed formulas of organic compounds; 2 (e) http://www.ocr.org.uk/Images/131287-...-resources.pdf

    MS: http://www.ocr.org.uk/Images/135164-...urces-june.pdf
    the products will be either an aldehyde or carboxylic acid

    so for each product oxidise both ends. the mark scheme allows a mixture of only oxidising one end but you might as well do the same thing on each side.
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    (Original post by Daniel__)
    Anyone mind helping me with this question about determining displayed formulas of organic compounds; 2 (e) http://www.ocr.org.uk/Images/131287-...-resources.pdf

    MS: http://www.ocr.org.uk/Images/135164-...urces-june.pdf
    If it is refluxed then it would oxidise completely and form carboxylic acids. now here you draw as if both alcohols have formed into carboxylic acids or just one.
    likewise, if distilled, then it partially oxidises and aldehyde is formed. as above it can be on both or just one alcohol.
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    (Original post by needtosucceed=))
    the products will be either an aldehyde or carboxylic acid

    so for each product oxidise both ends. the mark scheme allows a mixture of only oxidising one end but you might as well do the same thing on each side.
    If it is refluxed then it would oxidise completely and form carboxylic acids. now here you draw as if both alcohols have formed into carboxylic acids or just one.
    likewise, if distilled, then it partially oxidises and aldehyde is formed. as above it can be on both or just one alcohol.
    Thanks.
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    (Original post by SAS18)
    what boards are you with?
    mine are wjec for bio, ocr for chem (obviously) an aqa for physics
    Mine are all OCR A
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    Can someone explain qu 2c)ii) on the jan 11 paper


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    (Original post by beautywithbrains)
    Can someone explain qu 2c)ii) on the jan 11 paper


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    the equations actual moles/theoretical moles x100

    so theoretical = 6.25/molar mass of butan-1-ol

    actual = 6.57/molar mass of butylethanoate

    divide actual answer by theoretical answer then x100
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    Does a ketone form under reflux? Or can it form through gentle heating and then distilling as with an aldehyde?


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    (Original post by Polypocus)
    Does a ketone form under reflux? Or can it form through gentle heating and then distilling as with an aldehyde?


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    I think its reflux
 
 
 
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