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Redox Titration- easy calc but i need your help ;) watch

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    Hey

    used to be a don at these but I don't know whats happening lol

    here it is :

    24.3cm3 of 0.02 mol dm-3 KmnO4 reacted with 20.0 cm3 of an iron (II) solution
    Calculate the molarity of the iron (II) solution

    please see attatched for what I've done so far
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    (Original post by CasualSoul)
    Hey

    used to be a don at these but I don't know whats happening lol

    here it is :

    24.3cm3 of 0.02 mol dm-3 KmnO4 reacted with 20.0 cm3 of an iron (II) solution
    Calculate the molarity of the iron (II) solution

    please see attatched for what I've done so far
    You have made a simple error.

    Manganate(VII) is an oxidising agent and changes the oxidation state of the iron(II) to iron(III).

    So your iron half equation is:

    Fe2+ --> Fe3+ + 1e
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    (Original post by charco)
    You have made a simple error.

    Manganate(VII) is an oxidising agent and changes the oxidation state of the iron(II) to iron(III).

    So your iron half equation is:

    Fe2+ --> Fe3+ + 1e
    oo right :rolleyes:

    says I must rate another member but you are so good at chemistry!!! Thanks
 
 
 
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