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Edexcel C3,C4 June 2013 Thread watch

1. http://www.school-portal.co.uk/Group...urceId=3992069

how would you do question 3)b)

2. (Original post by Westeros)
Integral of 2/(2x-1) you wrote as ln|2x-1| is this correct?
Also don't forget +C on your second line
It is because you have to divide by the differential within the brackets
3. (Original post by keromedic)
I've no idea how to draw graphs from parametric equations. Eek
Don't worry, not on the specification.
4. (Original post by orange94)
Well I did! You right!

Unless anyone here objects to 1/3 being pulled out.

Here is what I did

Attachment 227735

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Cheers I had to put it in a weird form in terms of p using the limits, but got there eventually.

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5. (Original post by Jskalkut)
It is because you have to divide by the differential within the brackets
(Original post by PythianLegume)
Do you think it isn't? One of us is missing something here.
Just testing
6. (Original post by otrivine)
http://www.school-portal.co.uk/Group...urceId=3992069

how would you do question 3)b)

It involves treating it as (1/2)[sin(3x+x) + sin(3x-x)] It's a ridiculously difficult identity to see, and I doubt an actual C4 paper would have it.
7. (Original post by Westeros)
Just testing
Glad to be kept on my toes
8. (Original post by otrivine)
http://www.school-portal.co.uk/Group...urceId=3992069

how would you do question 3)b)

Manipulate the addition identities from C3 formulae sheet.

If you have sin3xcosx

Then sin (3x + x) = sin3xcosx + cos3xsinx (1)
then sin (3x - x) = sin3xcosx - cos3xsinx (2)

Therefore sin (3x + x) + sin (3x - x) = sin3xcosx (1) + (2)

therefore sin4x + sin2x = sin3xcosx

therefore just integrate sin4x + sin2x
9. (Original post by Kardy)
Manipulate the addition identities from C3 formulae sheet.

If you have sin3xcosx

Then sin (3x + x) = sin3xcosx + cos3xsinx
then sin (3x - x) = sin3xcosx - cos3xsinx

Therefore sin (3x + x) + sin (3x - x) = sin3xcosx

therefore sin4x + sin2x = sin3xcosx

therefore just integrate sin4x + sin2x
I see! that was a hard one to identify okay,

did you do

sin3xcosx + cos3xsinx - ( sinxcosx - cos3xsinx)

sin3xcosx + cos3xsinx ?

then ?...

thank you
10. can anyone tell me the basic rules for differentiation of ln and e^x
11. (Original post by otrivine)
http://www.school-portal.co.uk/Group...urceId=3992069

how would you do question 3)b)

Using the product to sum formula.

I've written it at the bottom on this sheet. The first one is the one that is relevant.

They are derived from the C3 trig. identities seen in the top right hand corner.(landscape)

12. having panic attack
13. (Original post by fayled)
Don't worry, not on the specification.
But it's in the book? Admittedly, just converting to Cartesian form and then drawing or drawing up a table of values before then drawing, but it's definitely in the book!
14. Does anyone know of a link to the current Edexcel A Level Mathematics Specification?
The one listed on their website currently points to a 404.
http://www.edexcel.com/migrationdocu...2%20180510.pdf
15. (Original post by otrivine)
I see! that was a hard one to identify okay,

did you do

sin3xcosx + cos3xsinx - ( sinxcosx - cos3xsinx)

sin3xcosx + cos3xsinx ?

then ?...

thank you

Hi, is the answer -1/8cos4x - 1/4cos2x + c before putting the limits in?
16. (Original post by amin666)
having panic attack
Calm down, it'll be fine! Don't panic
17. (Original post by Fortitude)
Hi, is the answer -1/8cos4x - 1/4cos2x + c before putting the limits in?

It is and you could have taken out the -1/2 as a constant. But that makes no difference.
18. (Original post by Fortitude)
Hi, is the answer -1/8cos4x - 1/4cos2x + c before putting the limits in?
Correct, can you show me please
19. Does anyone have a (link to)/(copy of) the current Edexcel A Level Mathematics Specification?
The one linked on their website currently points to a 404.
http://www.edexcel.com/migrationdocu...2%20180510.pdf
20. (Original post by MasterYi)
It is and you could have taken out the -1/2 as a constant. But that makes no difference.
do you have working for that question by any chance

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