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    Team no sleep :|


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    morning
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    I hope I don't feel sleepy in the exam I'll try and get 2 hours of sleep if I can!
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    Brings me comfort to know I'm not the only one up tonight for chemistry
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    OK QUESTION, CU2+ IN EXCESS NAOH?? i have got two answers, one is [Cu(H2O)4(OH)2] and the other says its amphoteric and gives [Cu(OH)4]2- help WHICH IS IT?? thank you in advance!!
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    Heya
    Can someone please tell me When you have a 3+ ion complex and you add (EDTA)4- what do you get?
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    (Original post by BerryB)
    The perfect ionic model states that all ions are perfect spheres, and the bonding is COMPLETELY ionic. i.e it has no covalent character
    Thanks
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    hey i was wondering when you have to draw a cell diagram, does the most positive electrode go on the left hand side? Help please
    thanks
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    (Original post by RoaringLion)
    The perfect ionic model states:

    All ions exist as perfect spheres
    AND
    There are forces of electrostatic attraction between ions.

    This would be worth 2 marks ma if it were to appear, that's the answer, hope it helps.



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    Thankyou, i think ive got it now
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    (Original post by rommy123)
    hey i was wondering when you have to draw a cell diagram, does the most positive electrode go on the left hand side? Help please
    thanks
    positive is on the right hand side of the cell diagram
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    (Original post by Atz23)
    Heya
    Can someone please tell me When you have a 3+ ion complex and you add (EDTA)4- what do you get?
    Cu(H20)6 2+ + EDTA4- ---> CU(EDTA)2- + 6H2O
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    (Original post by Anshul91)
    positive is on the right hand side of the cell diagram
    Ooooh okay, better not make this mistake in the exam, thanks
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    (Original post by Anshul91)
    Cu(H20)6 2+ + EDTA4- ---> CU(EDTA)2- + 6H2O
    Thank
    what about a 3+ complex + (EDTA)4-?
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    (Original post by Atz23)
    Thank
    what about a 3+ complex + (EDTA)4-?
    same you just change the charge on the complex ion
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    (Original post by crc290)
    Reduction:
    H2O2 + 2H+ + 2e- \rightarrow 2H2O or H2O2 + 2e- \rightarrow 2OH-
    Oxidation:
    H2O2 \rightarrow O2 + 2H+ + 2e-

    Cobalt (II) in ammoniacal solution is [Co(NH3)6]2+. It can be oxidised to [Co(NH3)6]3+, but there is no ligand substitution

    Hope this helps
    Thankyou I meant that initially the water molecules are substituted by the ammonia, if that's right
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    (Original post by HeraXD)
    OK QUESTION, CU2+ IN EXCESS NAOH?? i have got two answers, one is [Cu(H2O)4(OH)2] and the other says its amphoteric and gives [Cu(OH)4]2- help WHICH IS IT?? thank you in advance!!
    I don't think it's amphoteric the first answer looks right to me
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    (Original post by Atz23)
    Thank
    what about a 3+ complex + (EDTA)4-?
    [Cr(H2O)6]3+ + EDTA4- --> [Cr(EDTA)]1- + 6H2O
    Good Luck in the exam
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    (Original post by Anshul91)
    Cu(H20)6 2+ + EDTA4- ---> CU(EDTA)2- + 6H2O
    Thank
    what about a 3+ complex + (EDTA)4-?

    (Original post by Anshul91)
    same you just change the charge on the complex ion
    Thank you
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    Lets just hope it's not a bull paper like June 12...
    that paper annoyed me so much, no matter what I did I got 0.1 for the gradient!



    also how is the ratio 3:5 can someone explain?
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    Al(H2O)6 3+ in excess OH is it Al(OH)4 - OR Al(OH)6 3- ???? THANKS
 
 
 
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