Google tom reds blog and go to chemistry(Original post by lifeisgood2012)
hiyaaaa guysssss...... does any of you know where i can find practice/ old legacy papers for each of the topics?
Posted from TSR Mobile
You are Here:
Home
> Forums
>< Study Help
>< Maths, science and technology academic help
>< Chemistry
>< Chemistry Exams
|
AQA CHEM5 A2 Chemistry - 19th June 2013 watch
-
Sherlockedd
- Follow
- 7 followers
- 2 badges
- Send a private message to Sherlockedd
- Thread Starter
Offline2ReputationRep:- Follow
- 721
- 25-05-2013 17:20
-
lifeisgood2012
- Follow
- 0 followers
- 0 badges
- Send a private message to lifeisgood2012
Offline0ReputationRep:- Follow
- 722
- 25-05-2013 19:37
i know this ain't the correct thread but the ppl here are probably very god with chem4.... so can some explain nmr to me and hw to deduce the structure of something using nmr (splitting, integration trace, functional groups)... i really dnt get this topic so if someone can give me their not or explain it to be i will be very grateful
-
- Follow
- 723
- 25-05-2013 20:28
Any predictions people
-
Sherlockedd
- Follow
- 7 followers
- 2 badges
- Send a private message to Sherlockedd
- Thread Starter
Offline2ReputationRep:- Follow
- 724
- 26-05-2013 11:19
Posted from TSR Mobile -
- Follow
- 725
- 26-05-2013 12:04
(Original post by lifeisgood2012)
i know this ain't the correct thread but the ppl here are probably very god with chem4.... so can some explain nmr to me and hw to deduce the structure of something using nmr (splitting, integration trace, functional groups)... i really dnt get this topic so if someone can give me their not or explain it to be i will be very grateful
no of peaks= number of hydrogen environments
integration ratio= how many hydrogen atoms there are in each environment. e.g if there are are 3 different hydrogen environment. In the first environment if there are 3 hydrogen atoms, in the second environment if there are 2 hydrogens and in the third environment there are 2 hydrogen atoms...then the integration ratio will be 32.
If you can bring up a question I may be able to help you. I'm no expert in this topic by any means but hope that helped you abit -
lifeisgood2012
- Follow
- 0 followers
- 0 badges
- Send a private message to lifeisgood2012
Offline0ReputationRep:- Follow
- 726
- 26-05-2013 13:17
for this module are we require to drawing a hess cycle?
-
- Follow
- 727
- 26-05-2013 13:19
(Original post by lifeisgood2012)
for this module are we require to drawing a hess cycle? -
- Follow
- 728
- 26-05-2013 13:19
(Original post by lifeisgood2012)
for this module are we require to drawing a hess cycle?
Posted from TSR Mobile -
lifeisgood2012
- Follow
- 0 followers
- 0 badges
- Send a private message to lifeisgood2012
Offline0ReputationRep:- Follow
- 729
- 26-05-2013 13:57
-
lifeisgood2012
- Follow
- 0 followers
- 0 badges
- Send a private message to lifeisgood2012
Offline0ReputationRep:- Follow
- 730
- 26-05-2013 13:57
(Original post by Hart1995)
I don't think so, aslong as you can workout the calculation.
Posted from TSR Mobile -
lifeisgood2012
- Follow
- 0 followers
- 0 badges
- Send a private message to lifeisgood2012
Offline0ReputationRep:- Follow
- 731
- 26-05-2013 14:13
why is it that the transition metals have similar properties issit because of the closeness in the s and the d energy sub level?
-
- Follow
- 732
- 26-05-2013 14:31
(Original post by lifeisgood2012)
for this module are we require to drawing a hess cycle? -
- Follow
- 733
- 26-05-2013 15:34
(Original post by lifeisgood2012)
why is it that the transition metals have similar properties issit because of the closeness in the s and the d energy sub level?
1. They can form a stable ion with a partially filled d-Orbital
2. They have variable oxidation states
3. They can form complex coloured ions -
- Follow
- 734
- 26-05-2013 18:02
Hello, anyone here dyslexic and really struggling with all the chemical formulas, names, and calculations?
I need some advice on what the best learning methods would be.
-
starfish232
- Follow
- 4 followers
- 0 badges
- Send a private message to starfish232
Offline0ReputationRep:- Follow
- 735
- 26-05-2013 18:21
Could someone please explain how the answer is 6 to question 4e(iii) on the jan 2011 paper. I don't understand how the multiple taste can be assumed to form 4 coordinate bonds with the Co.
Is it 6 because you just assume it's going to form the octahedral shape that most complexes are seen as?
Thanks
http://filestore.aqa.org.uk/subjects...W-MS-JAN11.PDF
http://filestore.aqa.org.uk/subjects...W-QP-JAN11.PDF -
- Follow
- 736
- 26-05-2013 18:39
(Original post by starfish232)
Could someone please explain how the answer is 6 to question 4e(iii) on the jan 2011 paper. I don't understand how the multiple taste can be assumed to form 4 coordinate bonds with the Co.
Is it 6 because you just assume it's going to form the octahedral shape that most complexes are seen as?
Thanks
http://filestore.aqa.org.uk/subjects...W-MS-JAN11.PDF
http://filestore.aqa.org.uk/subjects...W-QP-JAN11.PDF
Ok this is a bit hard to explain. In q4e(ii) you have to assume the PR forms 4 CO-ordiante bonds as we know the H20 can only form 1 and there are 2 molecules of h20.
Hence in next questions there is 1PR(4 co-ordinate bonds), 1 unidentate ligand(1 co-ordinate bond) and 1 Cyanide molecules(1 co-ordinate bonds)
Hence the coordination number is 4 plus 1 plus 1 =6
Hope that helpsLast edited by cheesypuff; 26-05-2013 at 18:44. -
frogs r everywhere
- Follow
- 9 followers
- 13 badges
- Send a private message to frogs r everywhere
Offline13ReputationRep:- Follow
- 737
- 26-05-2013 18:41
(Original post by starfish232)
Could someone please explain how the answer is 6 to question 4e(iii) on the jan 2011 paper. I don't understand how the multiple taste can be assumed to form 4 coordinate bonds with the Co.
Is it 6 because you just assume it's going to form the octahedral shape that most complexes are seen as?
Thanks
http://filestore.aqa.org.uk/subjects...W-MS-JAN11.PDF
http://filestore.aqa.org.uk/subjects...W-QP-JAN11.PDF
In the reaction above, you have:
PR(aq) + [Fe(H2O)6]2+(aq) → [FePR(H2O)2]2+(aq) + 4H2O(I)
As you can see that the Pophyrin ring has replaced 4 water molecules. Thus, it must be a mutlidendate ligand, with 4 lone pairs of electrons.
The final complex has these compounds acting as ligands
CN- ( 1 co-ordinate bond)
A unidentate ligand ( 1 co-ordinate bond)
PR (4 co-ordinate bonds)
The complex has 6 co-ordinate bonds, so its co-ordination number must be six. (octahedral). Does that make sense? -
frogs r everywhere
- Follow
- 9 followers
- 13 badges
- Send a private message to frogs r everywhere
Offline13ReputationRep:- Follow
- 738
- 26-05-2013 18:44
(Original post by cheesypuff)
Hello,
Ok this is a bit hard to explain. In q4e(ii) you have to assume the PR forms 4 CO-ordiante bonds as we know the H20 can only form 1 and there are 2 molecules of h20.
Hence in next questions there is 1PR(4 co-ordinate bonds), 1 unidentate ligand(1 co-ordinate bond) and 2 Cyanide molecules(2 co-ordinate bonds)
Hence the coordination number is 1 plus 1 plus 2=4
Hope that helps -
starfish232
- Follow
- 4 followers
- 0 badges
- Send a private message to starfish232
Offline0ReputationRep:- Follow
- 739
- 26-05-2013 18:50
(Original post by cheesypuff)
Hello,
Ok this is a bit hard to explain. In q4e(ii) you have to assume the PR forms 4 CO-ordiante bonds as we know the H20 can only form 1 and there are 2 molecules of h20.
Hence in next questions there is 1PR(4 co-ordinate bonds), 1 unidentate ligand(1 co-ordinate bond) and 1 Cyanide molecules(1 co-ordinate bonds)
Hence the coordination number is 4 plus 1 plus 1 =6
Hope that helps -
- Follow
- 740
- 26-05-2013 18:50
(Original post by frogs r everywhere)
Your reasoning is correct, but the co-ordination number isn't 4. Look at my post above.
- AQA A-Level Chemistry (7405) Exam Thread - June 13th ...
- AQA CHEM4 A2 Chemistry - 9 June 2014
- Edexcel A2 C3 Mathematics 12th June 2015
- Current Year 13 Thread (2013/14) - Mark 2
- A2 SCLY4 Crime and Deviance Sociology Exam June 2014
- Edexcel 6BIO5 ~ 20h June 2014 ~ A2 Biology
- The Uber "Feeling the A Level stress" 2014 Thread
- A Level Results Day: 13th August 2015: Grade Boundaries.
- MEDICINE - *RESULTS DAY 2014* - AS Level Results ...
- Road to A*A*A*
-
Chemistry, Biological and Medicinal Chemistry with a year in York
University of York
-
Durham University
-
Medicinal and Biological Chemistry
University of Edinburgh
-
University of Oxford
-
Materials Chemistry with External Placement
University of St Andrews
-
Chemistry with a Year in Industry
University of Leeds
-
Chemistry with Study Abroad (4 years)
University of Birmingham
-
Keele University
-
Secondary Education (Chemistry)
University of Dundee
-
Chemistry with Science Foundation Year
Keele University
We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.
- charco
- Mr M
- Changing Skies
- F1's Finest
- rayquaza17
- Notnek
- RDKGames
- davros
- Gingerbread101
- Kvothe the Arcane
- TeeEff
- The Empire Odyssey
- Protostar
- TheConfusedMedic
- nisha.sri
- claireestelle
- Doonesbury
- furryface12
- Amefish
- harryleavey
- Lemur14
- brainzistheword
- Rexar
- Sonechka
- TheAnxiousSloth
- EstelOfTheEyrie
- CoffeeAndPolitics
- an_atheist
- Labrador99
- EmilySarah00