AQA Core 4 - Monday 10th June 2013 (AM) - Official ThreadWatch
Good Luck with your revision!
Any chance of getting the January 2013 paper?
So make that equal 2sinx + 5cosx
you the the sinx cancel on one side and cosx on the other,
leaving you with Rcosa = 2, and Rsina = 5
Square both the equations then add them,
giving R^2(cos^2a) + R^2(sin^2a)= 4 + 25
Take R^2 factor out >> R^2(cos^2a + sin^2a) = 29
sin^2 + cos^2 = 1 right?
so R^2 = 29
R is the maximum value because you've stretched the curve in the y direction by R
so the maximum value is root29
sec^2y/cos^2(2x) x dy/dx = 2"
Anyone help please? thanks!