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AQA Core 4 - Monday 10th June 2013 (AM) - Official Thread Watch

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    (Original post by Jamie T)
    that's all I did too. probs just the one mark.
    Damn. It seems so obvious now that k should be pi/6 grrrrr
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    The fact that there were loads of messy calculations made me think I was doing it wrong all the time...
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    Can I get full marks on 8a by using inspection, I got the right answer I think?
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    (Original post by I Hate Edexcel)
    The fact that there were loads of messy calculations made me think I was doing it wrong all the time...
    Same. I think I went over the easy questions a few times each because the calculations were so chaotic.
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    (Original post by olliefoss)
    Can I get full marks on 8a by using inspection, I got the right answer I think?
    Absolutely. It would be ridiculous if they didn't give you the full marks as long as you got the right answer at the end too.
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    (Original post by Student Number 4)
    Same. I think I went over the easy questions a few times each because the calculations were so chaotic.
    Yeah, so then I was rushed to do the harder questions. Wahhh... I'd personally say this paper was harder than January 13.
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    (Original post by Nebula)
    I'm not completely sure but I think it's (-3, -11, 10).
    Could you run over your working of how you found E?
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    (Original post by I Hate Edexcel)
    Damn. It seems so obvious now that k should be pi/6 grrrrr
    I think you should change Edexcel to AQA in your name.
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    Anyone remember what the last two parts of question 2 were? The alpha and beta one

    Trying to compose a mark scheme
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    for findng the value of k , i thought it was degrees so i put k=30 as then 12x30 = 360 , how many marks would i lose for this ?
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    (Original post by I Hate Edexcel)
    Yeah, so then I was rushed to do the harder questions. Wahhh... I'd personally say this paper was harder than January 13.
    Atleast you attempted the harder questions . I left the last question out D:
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    (Original post by olliefoss)
    Can I get full marks on 8a by using inspection, I got the right answer I think?
    No, you will be terminated. Of cause you would get the marks!
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    (Original post by fizzbizz)
    Anyone remember what the last two parts of question 2 were? The alpha and beta one

    Trying to compose a mark scheme
    It was something to do with finding cos and sin beta so it might have been involving sin(2beta)? I'll update if I remember
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    For that vector question, where it said find E, did anybody think/do this.

    Okay so they said the area of triangle ACD is 3 times the area of ACE.

    So seeing AC remains the same for both triangles, the only thing that changes is the distance of the base (CD or CE).

    I worked out the |CD| to be rt17 then surely |CE| must be 3rt17

    Then I work out the |CE| in terms of mu and got as far as u^2 = +3 or -3.

    Then put the back into the general vector for OE and you get E is either (-3,11,10) or (9,7,-2)?
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    (Original post by fizzbizz)
    Anyone remember what the last two parts of question 2 were? The alpha and beta one

    Trying to compose a mark scheme
    I think the last part was: Prove cos(alpha - beta) = 2/5 (k +sqrt5)
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    (Original post by stuart_aitken)
    good to know someone got the same as me!!!

    I'm pretty sure the equation was 32x/ tcos(t*pi/4)

    My working led to:

    16x^2 = (4t/pi)(sin(t*pi/4)) + (16/pi^2)(cos(t*pi/4))

    when x=4 and t=0, this gives c= 256 - 16/pi^2


    Nooooo how the hell did I just get 16/pi^2 for c?
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    (Original post by Student Number 4)
    Atleast you attempted the harder questions . I left the last question out D:
    Oh noooo That was an evil paper.
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    What did anyone get for part E of the vectors equation?? I got 17u = 3x(17) and u = plus or minus three or something like that that ?!
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    I got 44% in the January 2013 paper, and this was worse phaha EVERYONE CHILL OUT YOURE ALL TSR CLEVERS!
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    I guess doing past papers was pretty useless....
    2008 to Jan 2013 doable June 2013 crazy hard
    2008-Jan2013
    Exponential growth and decay
    Rsin(x+y)

    june 2013
    Knowing that 2X-1=0 calculate the mass of the sun to 6 s.f.

    hopefully grade boundaries are really low
 
 
 
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