Join TSR now and get all your revision questions answeredSign up now
    Offline

    0
    ReputationRep:
    (Original post by emah123)
    was is just me or was that the HARDEST PAPER EVER. good bye to medical school
    ahh that's what I'm thinking I so hope I've got a B or I'll be so upset for the next year.. min. God it's stressing me out looking at the answers people got and I didn't!
    Offline

    1
    ReputationRep:
    (Original post by keepontrying)
    I meant to put 6H20 at the end I just forgot to type it and yours doesn't balance electrically but still may be correct!
    It does o.O

    Oops I meant +3
    Offline

    0
    ReputationRep:
    Overall I thought the paper was hard but doable. Looking through the answers people have posted I seem to be the only one who calculated a value of 3.55 for the buffer solution pH, did anyone else get this?
    Offline

    0
    ReputationRep:
    (Original post by talliehughes)
    I got both 3.99 and put 16.75 for the kc but I don't think they'll be too picky when it comes to rounding numbers
    The 16.75 was right, but they asked for 3 sigfig :/
    Offline

    2
    ReputationRep:
    (Original post by Little Wing)
    NH3 acts as a reducing agent anyone?
    I guessed acting as a reducing agent as well. Is it right though ?? :\

    ... by the way here is the link for the 'Dimethylglyoxime' structure
    • PS Helper
    Offline

    0
    ReputationRep:
    (Original post by Little Wing)
    NH3 acts as a reducing agent anyone?
    I put that it acted as a proton accepter, but I could be wrong
    Offline

    2
    ReputationRep:
    Hoping it's like 62 for a B :L
    Offline

    2
    ReputationRep:
    (Original post by Allotropy)
    Overall I thought the paper was hard but doable. Looking through the answers people have posted I seem to be the only one who calculated a value of 3.55 for the buffer solution pH, did anyone else get this?
    how did u work it out man

    how were u meanto work out the conc of the salt ????
    Offline

    0
    ReputationRep:
    why order of H2O was zero?
    Offline

    15
    ReputationRep:
    (Original post by Little Wing)
    NH3 acts as a reducing agent anyone?
    It was acting as a base.
    Offline

    0
    ReputationRep:
    (Original post by Allotropy)
    Overall I thought the paper was hard but doable. Looking through the answers people have posted I seem to be the only one who calculated a value of 3.55 for the buffer solution pH, did anyone else get this?
    ib got 3.55/3.57, definitrly out of those two
    Offline

    1
    ReputationRep:
    (Original post by jess_m94)
    I put that it acted as a proton accepter, but I could be wrong
    I put that also - that it acts as a base to accept the proton from that weird molecule.

    (Original post by freetown)
    I guessed acting as a reducing agent as well. Is it right though ?? :\

    ... by the way here is the link for the 'Dimethylglyoxime' structure
    Oh for gods sake I misread the question and drew that very molecule but with a hydrogen removed. I thought it wanted the ligand
    Offline

    1
    ReputationRep:
    (Original post by tangaroo)
    i could've sworn it wasn't THAT bad guys?
    If you tell me you enjoyed it, I will cry...real tears. :unimpressed:
    • Study Helper
    Offline

    3
    ReputationRep:
    (Original post by jess_m94)
    I put that it acted as a proton accepter, but I could be wrong
    I said this too and that it's used to neutralise excess acid?
    Offline

    0
    ReputationRep:
    (Original post by Allotropy)
    Overall I thought the paper was hard but doable. Looking through the answers people have posted I seem to be the only one who calculated a value of 3.55 for the buffer solution pH, did anyone else get this?
    I did, but i'm pretty sure it's wrong.
    Offline

    2
    ReputationRep:
    For the redox one I think I did:

    2[Fe(H2O)6]^3+ + Al ====> 2[Fe(H2O)6]^2+ + Al^2+

    Which seems completely wrong to me. Not sure I should have included the complexes. Oh well. Don't know if that's exactly what I put; can't remember what the Aluminium was oxidised to...


    For the ligand substitution one I think I did:

    [Fe(H2O)6]^3+ + 6CN^- ====> [Fe(CN)6]^3- + 6H2O



    For the use of NH3 in the bidentate ligand question:

    NH3 oxidised the ligand (or words to that effect)


    The amount of answers I have no idea are correct or not is too damn high..
    Offline

    0
    ReputationRep:
    (Original post by amin666)
    why order of H2O was zero?
    I just wrote because its concentration doesn't affect the rate. I meant to go back at the end to expand on it, but I ran out of time.
    Offline

    0
    ReputationRep:
    (Original post by keepontrying)
    did any one get [fe(h20)6]3+ + 6KCN-------> [Fe(CN)6]3-6K+ +6H20
    yea kind of i wrote 6KOH in the end and
    Offline

    1
    ReputationRep:
    (Original post by freetown)
    I guessed acting as a reducing agent as well. Is it right though ?? :\

    ... by the way here is the link for the 'Dimethylglyoxime' structure
    i put it as a base... proton acceptor... not toos ure on that one! but woop about the structure
    • PS Helper
    Offline

    0
    ReputationRep:
    (Original post by amin666)
    why order of H2O was zero?
    I just put that it has no effect on rate of reaction, so when conc h20 increases, rate of reaction remains the same
 
 
 
Poll
Which pet is the best?

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Quick reply
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.