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    Hi, I don't actually take a-level maths but I do A2 physics and I'm really struggling at the moment. Could someone please help me rearranged this formula...

    Basically, we plot a graph of V/t and calculate a gradient.

    We're then given the equation:
    V=V0e-t/RC

    We know the value for our gradient (V/t), V0 and R. We need to rearrange the equation to get the value for C.

    Everyone in my class does a-level maths and I know they ln it all and use y=mx+c but I don't really understand the relevance of that.

    I'd be so grateful for any help on this. I have an accessed practical soon and I need to be able to find the value of C from the above data myself in exam conditions. Thank you sooooo much! x
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    (Original post by Sparkliest)
    Hi, I don't actually take a-level maths but I do A2 physics and I'm really struggling at the moment. Could someone please help me rearranged this formula...

    Basically, we plot a graph of V/t and calculate a gradient.

    We're then given the equation:
    V=V0e-t/RC

    We know the value for our gradient (V/t), V0 and R. We need to rearrange the equation to get the value for C.

    Everyone in my class does a-level maths and I know they ln it all and use y=mx+c but I don't really understand the relevance of that.

    I'd be so grateful for any help on this. I have an accessed practical soon and I need to be able to find the value of C from the above data myself in exam conditions. Thank you sooooo much! x
    \frac{V}{V_0}=e^{-\frac{t}{RC}}
    so
    ln\frac{V}{V_0}=-\frac{t}{RC}
    Solve for C
 
 
 
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