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# Logarithams watch

1. sole equation to find x in terms of a

2log(2x)=1+loga

Could you please show working out thank you
2. (Original post by chuckynoriss)
sole equation to find x in terms of a

2log(2x)=1+loga

Could you please show working out thank you
Don't do fully worked solutions - against forum policy, with good reason.

To get you started, try and arrange each side of the equation to get it into the form "log(something)".
3. Also you need to know the base for this question... is it 10 ?
4. is the answer log(a)/log(2) ? i think i got it
5. (Original post by sonyeric33)
is the answer log(a)/log(2) ? i think i got it
This is incorrect.
6. (Original post by sonyeric33)
is the answer log(a)/log(2) ? i think i got it
No
7. (Original post by chuckynoriss)
sole equation to find x in terms of a

2log(2x)=1+loga

Could you please show working out thank you
Use the log rules.

Hint: Change 1 into log(10)
8. its just a guess x= 0.398/[log (2/a)] i need to revise logs xD
9. (Original post by sonyeric33)
its just a guess x= 0.398/[log (2/a)] i need to revise logs xD
In the final equation of x in terms of a there should be no logs.
10. ahhh ok i got it im just stupid, root-> (5a/2)
11. (Original post by sonyeric33)
ahhh ok i got it im just stupid, root-> (5a/2)
THis is correct, although the convention would be to write this as sqrt(10a)/2 to avoid an irrational denominator

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