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    sole equation to find x in terms of a

    2log(2x)=1+loga

    Could you please show working out thank you
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    (Original post by chuckynoriss)
    sole equation to find x in terms of a

    2log(2x)=1+loga

    Could you please show working out thank you
    Don't do fully worked solutions - against forum policy, with good reason.

    To get you started, try and arrange each side of the equation to get it into the form "log(something)".
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    Also you need to know the base for this question... is it 10 ?
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    is the answer log(a)/log(2) ? i think i got it
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    (Original post by sonyeric33)
    is the answer log(a)/log(2) ? i think i got it
    This is incorrect.
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    (Original post by sonyeric33)
    is the answer log(a)/log(2) ? i think i got it
    No
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    (Original post by chuckynoriss)
    sole equation to find x in terms of a

    2log(2x)=1+loga

    Could you please show working out thank you
    Use the log rules.

    Hint: Change 1 into log(10)
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    its just a guess x= 0.398/[log (2/a)] i need to revise logs xD
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    (Original post by sonyeric33)
    its just a guess x= 0.398/[log (2/a)] i need to revise logs xD
    In the final equation of x in terms of a there should be no logs.
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    ahhh ok i got it im just stupid, root-> (5a/2)
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    (Original post by sonyeric33)
    ahhh ok i got it im just stupid, root-> (5a/2)
    THis is correct, although the convention would be to write this as sqrt(10a)/2 to avoid an irrational denominator
 
 
 
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