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Stoke's Theorem (Multivariable Calculus) watch

1. Q4 here: http://www.maths.ox.ac.uk/system/fil...1/9/sheet8.pdf

We can get vector B by setting vector R to be zero, but that all I have so far. Am I missing something obvious, or is there a some work involved?

Would prefer to get hints, rather than the solution.

Thanks.
2. (Original post by twig)
Q4 here: http://www.maths.ox.ac.uk/system/fil...1/9/sheet8.pdf

We can get vector B by setting vector R to be zero, but that all I have so far. Am I missing something obvious, or is there a some work involved?

Would prefer to get hints, rather than the solution.

Thanks.
Have you tried expanding:
|r-R|^2=|R|^2+|r|^2-2r.R
?
Sorry if I'm stating the obvious.
3. (Original post by ben-smith)
Have you tried expanding:
|r-R|^2=+|r|^2-2r.R
?
Sorry if I'm stating the obvious.
Hello!

Yeah sure I have tried that. Then: |r|^2 part of the integral can be the vector B, and (faily sure, but I could be wrong) the constant |R|^2 part dissappears as we are integrating across a closed loop. This leaves the -2r.R part still inside the integral. I am failing to show this is perpendicual to R / can be written explicitly as RcrossA for some A. (Have a feeling we must find A, as that will probably be used in the second part).
4. bump
5. Not entirely certain whether it'll go anywhere but perhaps considering might help?
6. (Original post by Farhan.Hanif93)
Not entirely certain whether it'll go anywhere but perhaps considering might help?
Hello,

I did try that without success. Maybe I will just let this q pass!
7. any takers?
8. (Original post by twig)
Just had another go at this and think I've got it:

By considering where is an arbitrary constant vector and is a scalar field, show that where .

If that's a bit too cryptic:
Stokes' theorem on af
9. (Original post by Farhan.Hanif93)
Just had another go at this and think I've got it:

By considering where is an arbitrary constant vector and is a scalar field, show that where .

If that's a bit too cryptic:
Stokes' theorem on af
Thanks.
Of course... yeah we did cover that scalar-corollary to Stoke's. That was sloppy for me to miss that!

Btw, how's Cam going? Any liking/disliking of certain topics?

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