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    During the synthesis of the ethyl ethanoate, why is ethanol, pure ethanoic acid and concentrated sulfuric acid heated under reflux??

    I'm struggling to understand why . Could someone please explain this. Thanks!

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    this isn't GCSE i'm pretty sure not sure what bits you don't understand, but the conc H2SO4 is just the catalyst.
    ethanol + ethanoic acid > ethyl ethanoate and water
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    It's heated under reflux to maximise the yield of ethyl ethanoate.
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    The reaction goes much faster when it's heated. However, ethanol's boiling point is quite low (78°C), and we don't want it to all evaporate off before it's had a chance to react. Therefore it's heated under reflux so that any ethanol that does boil off gets condensed back and is given another chance to react.
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    (Original post by such)
    The reaction goes much faster when it's heated. However, ethanol's boiling point is quite low (78°C), and we don't want it to all evaporate off before it's had a chance to react. Therefore it's heated under reflux so that any ethanol that does boil off gets condensed back and is given another chance to react.

    Ok, thanks a lot. You really helped me understand.
    Could you also explain why the reaction mixture is distilled after refluxing?
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    (Original post by Zaphod77)
    It's heated under reflux to maximise the yield of ethyl ethanoate.

    Thank you
    Could you also explain why the reaction mixture is distilled after refluxing?
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    (Original post by park1996)
    Thank you
    Could you also explain why the reaction mixture is distilled after refluxing?
    It's distilled to take out all the leftover ethanol and any impurities, so that just the ethyl ethanoate is collected
 
 
 
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