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    Hi! I'm doing some GCSE maths homework and there's one question which I know the answer to but am confused about the process

    "Miss Tuck started teaching at the school on a salary of £14500, how many years will it be until she is earning a salary of over £20000?"

    the pretext is

    "The headmaster of a new school offered his staff an annul pay increase of 5% for every year they stayed with the school"

    I know the answer is 7 years (I think), but should you work this out using a trial and error method or is there a more algebraic way of doing it?

    thanks! I would be grateful for any kind of response
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    (Original post by jojotheflower)
    Hi! I'm doing some GCSE maths homework and there's one question which I know the answer to but am confused about the process

    "Miss Tuck started teaching at the school on a salary of £14500, how many years will it be until she is earning a salary of over £20000?"

    the pretext is

    "The headmaster of a new school offered his staff an annul pay increase of 5% for every year they stayed with the school"

    I know the answer is 7 years (I think), but should you work this out using a trial and error method or is there a more algebraic way of doing it?

    thanks! I would be grateful for any kind of response
    There is an algebraic approach but that is an A level topic

    At GCSE Trial & Improvement is the method
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    (Original post by jojotheflower)
    Hi! I'm doing some GCSE maths homework and there's one question which I know the answer to but am confused about the process

    "Miss Tuck started teaching at the school on a salary of £14500, how many years will it be until she is earning a salary of over £20000?"

    the pretext is

    "The headmaster of a new school offered his staff an annul pay increase of 5% for every year they stayed with the school"

    I know the answer is 7 years (I think), but should you work this out using a trial and error method or is there a more algebraic way of doing it?

    thanks! I would be grateful for any kind of response
    You just need to find \sqrt[n]{ \frac{20000}{14500}} and find the first value of n that produces a value lower than 1.05 (the multiplier for a 5% increase).
 
 
 
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