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    I know that if you have e2ln(x) you could use the 'power rule' and move the '2' so you get:

    eln(x^2) = x2

    However, since 2ln(x) = ln(x) x 2, what if you do this:


    e2ln(x) = eln(x)*2 then cancel the 'e' and 'ln' terms (* means multiply btw)
    and you get (x)*2 = 2x ?

    I am probably making a simple mistake but I just want to clarify this since its causing me a headache
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    (Original post by GPODT)
    I know that if you have e2ln(x) you could use the 'power rule' and move the '2' so you get:

    eln(x^2) = x2

    However, since 2ln(x) = ln(x) x 2, what if you do this:


    e2ln(x) = eln(x)*2 then cancel the 'e' and 'ln' terms (* means multiply btw)
    and you get (x)*2 = 2x ?

    I am probably making a simple mistake but I just want to clarify this since its causing me a headache

    From e^{\ln x*2} you get (e^{\ln x})^2 = (x)^2 = x^2
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    You can't cancel the right hand side to get 2x. 2 isn't the inverse of an exponential function, only ln(x) is, you can't just say that since it's multiplying ln(x) it's legal to remove the 'e.'
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    (Original post by TenOfThem)
    From e^{\ln x*2} you get (e^{\ln x})^2 = (x)^2 = x^2
    :facepalm:

    perfect!
 
 
 
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