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# ln watch

1. I know that if you have e2ln(x) you could use the 'power rule' and move the '2' so you get:

eln(x^2) = x2

However, since 2ln(x) = ln(x) x 2, what if you do this:

e2ln(x) = eln(x)*2 then cancel the 'e' and 'ln' terms (* means multiply btw)
and you get (x)*2 = 2x ?

I am probably making a simple mistake but I just want to clarify this since its causing me a headache
2. (Original post by GPODT)
I know that if you have e2ln(x) you could use the 'power rule' and move the '2' so you get:

eln(x^2) = x2

However, since 2ln(x) = ln(x) x 2, what if you do this:

e2ln(x) = eln(x)*2 then cancel the 'e' and 'ln' terms (* means multiply btw)
and you get (x)*2 = 2x ?

I am probably making a simple mistake but I just want to clarify this since its causing me a headache

From you get
3. You can't cancel the right hand side to get 2x. 2 isn't the inverse of an exponential function, only ln(x) is, you can't just say that since it's multiplying ln(x) it's legal to remove the 'e.'
4. (Original post by TenOfThem)
From you get

perfect!

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Updated: March 19, 2013
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