It's how much something goes up by for every 1. You'll have to put it in reference to the question. eg. if you where looking at how loud something is and the distance it is, y being how loud and x being the distance, 7.7 would be how loud y is per metre of distance. Sorry if that sounds confusing if you told me the scenario they give I'd be able to tell you?

Original post by Air1337

Let's assume we have a regression line for the age of children (x) and the amount of homework they do (y). Then for every 1 year of age, homework increases by 7.7.

thank you so much :smile:

Reply 203

Salvatore8

1

Original post by Meera.S.

whats the triangle method? help please

Here's an Example, hope it helps! if not dont confuse yourself with it; it takes some time getting used to it

Interpolation.JPG35.0KB

Reply 204

Fortitude

16

When plotting a regression line, you plot the mean of x & the mean of y, do you also plot the y-intercept so (0,a) ?

Reply 205

Amydx6

3

When you do a box plot and you calculate the outliers where does the 'whisker' go to the next highest/lowest value or does it go to th value you calculated to be the boundary for an outlier?

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Reply 206

Amydx6

3

Original post by Fortitude

When plotting a regression line, you plot the mean of x & the mean of y, do you also plot the y-intercept so (0,a) ?

No you just do the mean point I think

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Reply 207

May-o2q

14

Original post by Meera.S.

Can some one help me, i get between the Q1 and Q3 thing..

which one is the upper/lower Q?

Q1 is lower quartile with 25% of the data and Q3 is upper quartile with 75% of the data

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Reply 208

Salvatore8

1

Original post by Meera.S.

whats the triangle method? help please

Mistake! I left out the part in blue in the last one!

Interpolation2.JPG34.7KB

Reply 209

Salvatore8

1

Original post by jadecross

Never heard of that :biggrin:

Have a look at the method in the book pg 22.

thanks, I'll have a look

Reply 210

B-Stacks

13

Original post by Amydx6

When you do a box plot and you calculate the outliers where does the 'whisker' go to the next highest/lowest value or does it go to th value you calculated to be the boundary for an outlier?

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The next highest/lowest value. Put a cross on the outlier.

Reply 211

simonb451

2. (a) State in words the relationship between two events R and S when P(R∩S) = 0
(1)
The events A and B are independent with P(A)=1/4 and P(A∪ B) = 2/3

Find
(b) P(B)

Could someone please explain this to me- i know it is probably very simple. Thankyou

Reply 212

B-Stacks

13

Original post by simonb451

2. (a) State in words the relationship between two events R and S when P(R∩S) = 0
(1)
The events A and B are independent with P(A)=1/4 and P(A∪ B) = 2/3

Find
(b) P(B)

Could someone please explain this to me- i know it is probably very simple. Thankyou

a) think about the different kind of probabilities. Independent, conditional or mutually exclusive.

b) think again as above. Have a look at your formula sheet if you still don't know

(edited 10 years ago)

Reply 213

Amydx6

3

Original post by simonb451

2. (a) State in words the relationship between two events R and S when P(R∩S) = 0
(1)
The events A and B are independent with P(A)=1/4 and P(A∪ B) = 2/3

Find
(b) P(B)

Could someone please explain this to me- i know it is probably very simple. Thankyou

For a) it means that they are mutually exclusive because they cannot happen together.
B) as they are independent you know that P(AnB) = P(A) x P(B)
You also know that P(AuB) = P(A) + P(B) - P(AnB)
Therefore...
P(AuB) = P(A) + P(B) - (P(A) x P(B))
So
2/3 = 1/4 + P(B) - (1/4 P(B))
And then you rearrange it as if P(B) was x

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Reply 214

simonb451

B) as they are independent you know that P(AnB) = P(A) x P(B)
You also know that P(AuB) = P(A) + P(B) - P(AnB)
Therefore...
P(AuB) = P(A) + P(B) - (P(A) x P(B))
So
2/3 = 1/4 + P(B) - (1/4 P(B))
And then you rearrange it as if P(B) was x

Substitution- thank you- the annoying thing is in C1 and C2 im aiming for 90%+ but in stats i do not get higher than about 50. Cant believe it is 2 days away. i went to see my teacher today and she gave me 2 minutes and did not help :smile:

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Reply 215

usycool1

19

Original post by Amydx6

When you do a box plot and you calculate the outliers where does the 'whisker' go to the next highest/lowest value or does it go to th value you calculated to be the boundary for an outlier?

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Either is fine. :smile:

Original post by jadecross

i don't understand where the Z is plotted on the diagram (if it is a positive or negative a in this case) e.g. how would i find the value of a if P(Z<a) = 0.0170? :frown:

Drawing a sketch for these is always very helpful.

P(Z < a) = 0.0170

Using symmetry of the curve:

P(Z > z) = 0.0170

P(Z < z) = 1 - 0.0170 = 0.9380

So z = 2.12.

Because P(Z < a) is less than 0.5, a will be negative.

So a = -2.12.

Make sense? :smile:

Reply 216

salini1995

U guys can u tell me the hardest s1 paper please becoz I want to wanna try it out
Thank u

Reply 217

Amydx6

3

Original post by simonb451

B) as they are independent you know that P(AnB) = P(A) x P(B)
You also know that P(AuB) = P(A) + P(B) - P(AnB)
Therefore...
P(AuB) = P(A) + P(B) - (P(A) x P(B))
So
2/3 = 1/4 + P(B) - (1/4 P(B))
And then you rearrange it as if P(B) was x

Substitution- thank you- the annoying thing is in C1 and C2 im aiming for 90%+ but in stats i do not get higher than about 50. Cant believe it is 2 days away. i went to see my teacher today and she gave me 2 minutes and did not help :smile:

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I know what you mean I'm doing further maths and stats is holding me back my other marks are above 90% and I was told stats was the easiest... I disagree

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