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# Help with 12 (definitely not 11) in my pic watch

1. Anyone? thanks
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2. anyone?:/
3. How can you get rid of the root 2 on the rhs?
4. (Original post by Matureb)
How can you get rid of the root 2 on the rhs?
times the bottom and top of the fraction by root 2

what do I do after that?:/
times the bottom and top of the fraction by root 2

what do I do after that?:/
Do that, then bring all x's to one side and factorise, then divide by the bracket for your solution. For simplification sake remember then as another method and then divide by the coefficient given to your whole x term
6. Or multiply everything by root 2. Then rearrange.
7. (Original post by Robbie242)
Do that, then bring all x's to one side and factorise, then divide by the bracket for your solution. For simplification sake remember then
how do we get it in the form they are looking?

edit, i got it

#thanks again robbiee
how do we get it in the form they are looking?
-> therefore notice that From here divide and rationalise
9. (Original post by Robbie242)
-> therefore notice that From here divide and rationalise
yea i got it, thanks very much robbie
yea i got it, thanks very much robbie
No problem
11. (Original post by Robbie242)
No problem
How do we do 12 a?:/
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How do we do 12 a?:/
Note that From this you can use your power to simplify them to ^3 and ^-3 Furthermore, set f(x)=5 then subtract 5 as it is on the end just leaving your x term accordingly, now you have a standard equation Solve it. (you may have to use inverse powers tell me when you get here)
13. (Original post by Robbie242)
Note that From this you can use your power to simplify them to ^3 and ^-3 Furthermore, set f(x)=5 then subtract 5 as it is on the end just leaving your x term accordingly, now you have a standard equation Solve it. (you may have to use inverse powers tell me when you get here)
i am up to (2x)^3=(3x)^-3

btw you are class at maths robbie... are your teachers not gutted you proved them wrong?:P
i am up to (2x)^3=(3x)^-3

btw you are class at maths robbie... are your teachers not gutted you proved them wrong?:P
Ok now this is how I'd do it this may seem a bit weird but its what I do
from this we notice that x^3 works well here, from this we can assert that 2x^6=3 therefore I am going to put my method here as well to see if it works though, by substituion let -> k^2=3/2 so Don't forget plus or minus, similarly this means its true.

so solve and I think you get the right answer. They aren't they're quite happy to see were topping league tables; selfish *******s
15. (Original post by Robbie242)
Ok now this is how I'd do it this may seem a bit weird but its what I do
from this we notice that x^3 works well here, from this we can assert that 2x^6=3 therefore I am going to put my method here as well to see if it works though, by substituion let -> k^2=3/2 so Don't forget plus or minus, similarly this means its true.

so solve and I think you get the right answer. They aren't they're quite happy to see were topping league tables; selfish *******s
so we just take the 6th root of 3/2 ? how on earth we do that without a calculator?
so we just take the 6th root of 3/2 ? how on earth we do that without a calculator?
Seems a bit farfetched tbh, you could write it as
17. (Original post by Robbie242)
Seems a bit farfetched tbh, you could write it as
I know.. what a rotten question..

haha
I know.. what a rotten question..

haha
Am I right btw? I'm not sure haha
19. (Original post by Robbie242)
Am I right btw? I'm not sure haha
I don't think so but you are very close... the answer is 1.14 to 3dp according to my book
20. (Original post by Robbie242)
I don't think so but you are very close... the answer is 1.14 to 3dp according to my book
You should be taking the 6th root of 9/4, not 3/2~

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