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# Help with 12 (definitely not 11) in my pic watch

I don't think so but you are very close... the answer is 1.14 to 3dp according to my book
2. Just multiply each term by
3. No idea why we are taking the 6th root of anything

Since

4. (Original post by TenOfThem)
No idea why we are taking the 6th root of anything

Since

Oops I was misled by the title of the thread!!
5. (Original post by TenOfThem)
No idea why we are taking the 6th root of anything

Since

but these terms are squared with a +5 on the end ?
so we just take the 6th root of 3/2 ? how on earth we do that without a calculator?
No, you should find that

This will give you an approx value of 1.14 (and you will need a calculator)
but these terms are squared with a +5 on the end ?
You're making it too complicated for yourself

The question tells you that f(x) = (something horrible) + 5
and asks you to solve f(x) = 5

So you just need to solve (something horrible) = 0

8. (Original post by davros)
You're making it too complicated for yourself

The question tells you that f(x) = (something horrible) + 5
and asks you to solve f(x) = 5

So you just need to solve (something horrible) = 0

May I ask how I got it wrong Davros, does the power of 2 on the outside also effect the coefficient? am I missing something?
9. (Original post by davros)
You're making it too complicated for yourself

The question tells you that f(x) = (something horrible) + 5
and asks you to solve f(x) = 5

So you just need to solve (something horrible) = 0

lol, i love how you put that haha

this was in a non calculator paper :l
10. (Original post by TenOfThem)
No idea why we are taking the 6th root of anything

Since

why do I get this?
<--- me right now
Attached Images

11. (Original post by Robbie242)
May I ask how I got it wrong Davros, does the power of 2 on the outside also effect the coefficient? am I missing something?

Why would you square it

(function)^2=0 means function=0
why do I get this?
<--- me right now
Because you have 3 where you should have 3/2
13. (Original post by Robbie242)
May I ask how I got it wrong Davros, does the power of 2 on the outside also effect the coefficient? am I missing something?
When you set the bracket equal to 0, you're basically left with

Multiply both sides by
to get

and you're virtually there!

I haven't checked your working earlier; you probably just made a minor slip somewhere
14. (Original post by TenOfThem)
Because you have 3 where you should have 3/2
but it says squared
15. (Original post by TenOfThem)

Why would you square it

(function)^2=0 means function=0
Oh I see I'd be exactly like (x+3)^2=0 so (x+3)=0 I see what you mean, my just being an idiot, /shame
16. (Original post by Robbie242)
May I ask how I got it wrong Davros, does the power of 2 on the outside also effect the coefficient? am I missing something?
If you actually square

but it says squared
Madfish I recently recalled this after TenOfThem kicked common sense in my brain. say with have a function f(x)=(x+3)^2 say f(x)=0
0=(x+3)^2 therefore (x+3)=0 no need to expand and expanding gets you a longer solution
18. (Original post by Robbie242)
Madfish I recently recalled this after TenOfThem kicked common sense in my brain. say with have a function f(x)=(x+3)^2 say f(x)=0
0=(x+3)^2 therefore (x+3)=0 no need to expand and expanding gets you a longer solution
ahh I see, tenofthem is such an ace at mathematics
ahh I see, tenofthem is such an ace at mathematics
Indeed she is, I hope to be as good as her one day
20. (Original post by TenOfThem)
If you actually square

Ah cheers for clearing that up, unlikely but could possibly come up in c2 so thanks!

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